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What is the approximate DC component in the output of a positive diode clamper with a peak inout of 20V?
i dnt know wats the answer
How does the positive clamper works in electronic circuits?
A negative clamper circuit is considered. It shifts original input signal in a downward direction.While positive input is applied, diode is forward biased. The output voltage is Vo which is equal barrier potential of the diode. The capacitor is charged to V-Vo.When negative input cycle, diode does not conduct because it is reverse biased and the capacitor can not discharge very much because time constant (RC) choosen is high. Now output is sum of input voltage and capacitor voltage and it is equal to -(2V - Vo). Now peak to peak output voltage is difference of output voltages when positive and negative half cycles and it is equal to V-(-(2V - Vo)) or 2V.In negative clamper, input signal is pushed downward and positive peak of the output signal coincides with zero level.In positive clamper circuit, unlike in negative clamper circuit, diode is connected reversely.There is no change in connection of capacitor. But resistor is connected after diode. Positive clamping circuit shifts a input signal in upward direction. The output of this circuit shows that negative peak of signal coincides with zero level.
What are the advantages and disadvantages of clamper circuits?
asd
Why voltage gain is high in op amp?
A practical opamp is designed to approach the characteristics of the ideal opamp as closely as possible. The open loop voltage gain of an ideal opamp is infinite, so while this is actually impossible to achieve practical opamps are built with as high an open loop voltage gain as possible.
Which of following OP amp is used to strengthen the week signal?
741 opamp
