FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
Depends on how big the motor is. A stronger motor will draw more amps then a weaker or less efficient motor. For example a wiper motor draws far less then a starter motor.
If the nameplate states 20 amps then that is the full load amperage when the motor is running. The start up current on the motor could reach 300% of the FLA depending on the type of motor and the load that is connected to the motor.
THE FIRST THING IS TAKE THE READING OFF LOAD AND SEE IF THEY ARE BALANCED. HAS THE MOTOR BEEN RECENTLY REWOUND? GET A MOTOR REPAIR COMPANY TO LOOK AT THE MOTOR AND SEE IF IT HAS BEEN WOUND CORRECTLY. IF THE STAR-DELTA WORKS CORRECTLY IT SHOULD START IN STAR FOR ABOUT FIVE TO TEN SECONDS AND GO INTO DELTA THIS IS DEPENDANT ON THE STARTING CURRENT THE MANUFACTURE OF THE SWITCH AND THE APPLICATION. CHECK ALL THREE PHASES ARE BALANCED AND IF THEY ARE THE MOTOR WINDINGS MAY NOT BE CORRECTLY WOUND. SOME HAVE STAR CONNECTIONS BUILT IN.LOOKING AT THE AMPERAGE THE LOAD REQUIREMENT IS ONLY A FRACTION OF WHAT YOU ARE GETTING SO IT LEAVES ONLY TWO THINGS I......MOTOR FAULT 2.....WHAT EVER THE MOTOR IS DRIVING IS PUTTING A MASSIVE PRESSURE ON THE MOTOR CAUSING IT TO OVERLOAD.
Read the specification plate on the motor to determine the amount of current that the motor uses, as well as the voltage and phase. Most likely, it will be a 3 phase motor, so you can't simply connect it to your house wiring, but without sufficient information, it is impossible to tell you all of the specifics. <<>> The code book rates the amperage of a three phase 40 HP motor by different voltages. at 200 volts - 120 amps, 230 volts - 104 amps, 460 volts - 52 amps and 575 volts - 52 amps. A breaker for a motor has to be sized to 250% of the motors full load amps. Also the wire size for a motor has to be 125% of the motor full load amps.
Full load amps (FLA) refer to the maximum current a motor draws under full load condition, while running load amps (RLA) refer to the current a motor draws while running under operating conditions. RLA is typically lower than FLA since motors are often not running at full load.
FLA is the nameplate amperage rating of the motor when it is running at its designed horsepower and on the motors designed voltage. 746 watts = 1 HP. The FLA of a 1 HP motor at 240 volts would be W = amps x volts, Amps = Watts/Voltage. 746/240 = 3.1 amps full load. Overload the motor and the amps go higher, motor running at no load amps are lower than FLA
To determine the running amps of a 45 kW motor, you would need to know the voltage at which it operates. You can use the formula: Amps = (kW x 1000) / (Volts x power factor). Once you have the voltage and power factor information, you can plug them into the formula to calculate the running amps.
Depends on how big the motor is. A stronger motor will draw more amps then a weaker or less efficient motor. For example a wiper motor draws far less then a starter motor.
The Full Load Amps, FLA is a rating for each winding of the motor. In this case the motor actually needs 4 amps running through it. As current needs to go somewhere (perferably not to ground) the 4 amps will circulate on you 2 Hots, the neutral isn't needed. 4A in, 4A out.
For a 2.5hp 240v continuous motor, the current draw would be around 10 amps. This can vary slightly depending on the motor's efficiency and other factors, but 10 amps is a good estimate to use for this motor.
If the nameplate states 20 amps then that is the full load amperage when the motor is running. The start up current on the motor could reach 300% of the FLA depending on the type of motor and the load that is connected to the motor.
When you first turn on a motor it is starting from a static position and more current is required to get the motor up to speed (Starting current) than to keep it running (running current). Since watts equals amps times voltage you can see the difference in wattage is related to current. If you look at watts as work being done it is obvious that it requires more work to get the motor running than to keep it running.
The only thing that will trip the starter, is the load of the motor. Check the motor leads to make sure you have not crossed them over coming from the motor junction box. If the motor current is normal nameplate full load amps when run across the line then reduce the timing of the timer on the switch over from star to delta.
It depends on whether the motor is run on load or whether it's running light.
To calculate the amps consumed by a motor running at 3736 watts in 230 volts for one hour, use the formula: Amps = Watts / Volts. Therefore, Amps = 3736 watts / 230 volts ≈ 16.23 amps consumed in that one hour.
THE FIRST THING IS TAKE THE READING OFF LOAD AND SEE IF THEY ARE BALANCED. HAS THE MOTOR BEEN RECENTLY REWOUND? GET A MOTOR REPAIR COMPANY TO LOOK AT THE MOTOR AND SEE IF IT HAS BEEN WOUND CORRECTLY. IF THE STAR-DELTA WORKS CORRECTLY IT SHOULD START IN STAR FOR ABOUT FIVE TO TEN SECONDS AND GO INTO DELTA THIS IS DEPENDANT ON THE STARTING CURRENT THE MANUFACTURE OF THE SWITCH AND THE APPLICATION. CHECK ALL THREE PHASES ARE BALANCED AND IF THEY ARE THE MOTOR WINDINGS MAY NOT BE CORRECTLY WOUND. SOME HAVE STAR CONNECTIONS BUILT IN.LOOKING AT THE AMPERAGE THE LOAD REQUIREMENT IS ONLY A FRACTION OF WHAT YOU ARE GETTING SO IT LEAVES ONLY TWO THINGS I......MOTOR FAULT 2.....WHAT EVER THE MOTOR IS DRIVING IS PUTTING A MASSIVE PRESSURE ON THE MOTOR CAUSING IT TO OVERLOAD.