String num = Integer.toString(12345); // Insert your Integer here.
int sum = 0;
for(int i = 0; i < num.length(); i++){
sum += Character.digit(num.charAt(i), 10);
}
System.out.println(sum); // Simply prints the sum of the digits to standard out.
///// ALTERNATE SOLUTION:
int num = 12345; // Insert your Integer here.
int sum = 0;
while (num > 0){
sum += num % 10;
num /= 10;
}
System.out.println(sum); // Simply prints the sum of the digits to standard out.
Assuming you've entered a multi-digit number whole number (an integer), then take the modus (%) of the number and 10. E.g., if the number input was 1234, then 1234 % 10 is 4. Thus the final digit is 4. Note that modus 10 is the same as dividing the number by 10 and taking the remainder.
Yes
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
The tricky part is getting the individual digits. There are basically two ways to do this: 1) Convert the number to a string, and use string manipulation to get the individual digits. 2) Repeatedly divide the number by 10. The digit is the remainder (use the "%" operator). To actually get the highest digit, initially assume that the highest digit is zero (store this to a variable, called "maxDigit" or something similar). If you find a higher digit, replace maxDigit by that.
This is often used to specify several possibilities For example, assuming you have the last digit of a number in a variable "lastDigit":if (lastDigit 5)// In this case, the number is divisible by 5
Assuming you've entered a multi-digit number whole number (an integer), then take the modus (%) of the number and 10. E.g., if the number input was 1234, then 1234 % 10 is 4. Thus the final digit is 4. Note that modus 10 is the same as dividing the number by 10 and taking the remainder.
sir , what is perfect no?
Yes
Just generate the Fibonacci numbers one by one, and print each number's last digit ie number%10.
The tricky part is getting the individual digits. There are basically two ways to do this: 1) Convert the number to a string, and use string manipulation to get the individual digits. 2) Repeatedly divide the number by 10. The digit is the remainder (use the "%" operator). To actually get the highest digit, initially assume that the highest digit is zero (store this to a variable, called "maxDigit" or something similar). If you find a higher digit, replace maxDigit by that.
Enter "java -version" into a terminal. If Java is installed, it will tell you the version number. If it is not installed, it will say "command not found."
Java Development Kits are best found on the Java website. There are a number of programmes that can be downloaded. It is also possible to get Java Development Kit downloads from the Oracle website.
If by system number you mean the version number of the Java language on the client computer, you can useSystem.getProperty("java.version"); .Or, if you want the Java virtual machine version number you can use System.getProperty("java.vm.version"); .Finally, if you want the version number of the operating system, you can use System.getProperty("os.version"); .
Math.sqrt(number) function is used to find the square root of a number.. try it
This is often used to specify several possibilities For example, assuming you have the last digit of a number in a variable "lastDigit":if (lastDigit 5)// In this case, the number is divisible by 5
You can use the Math.sqrt() method.
Head First Java book covers, core java 1.5 [Tiger].