Either (1) determine the power of each branch, and add them together, or (2) multiply the load current by the supply voltage.
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It's the ratio of the total power of the two motors and their total apparent power (input side, of course.)
For lamps in parallel, it's straightforward, as you only need to add the individual power ratings to find the total power rating and multiply this value for the time over which they operate, to determine the energy dissipation.For lamps in parallel, it's far more complicated. Lamps in parallel are not subject to their rated voltages and, so, cannot operate at their rated powers. In fact, the lamp with the lowest power rating will actually burn the brightest! Trying to calculate what is going on is further complicated by the fact that there is significant difference in the resistance of a lamp when it is operating at its operating temperature and when it is cold, and you cannot determine these resistances theoretically. So, while you can determine the answer to your question experimentally -by measuring the current and voltage- it is not practical to calculate the answer you are looking for.
If a 'parallel' circuit has more than one load in its (not "it's"!) branches, then it is not a parallel circuit, but a series-parallel circuit! To resolve the circuit, you must first resolve the total resistance of the loads within each branch.
In this case, to get the equivalent resistance, first you use the parallel formula (1/R = 1/R1 + 1/R2) to calculate the equivalent resistors in parallel. Then you calculate the series resistance of this combination, with the other resistor.
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.