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Problem Statement for LCM:
Enter Two digits by a user and get its LCM
Answer:
#include
#include
void main()
{
int x,y,i,j;
clrscr();
printf("Enter Two Digits");
scanf("d",&x,&y);
for(i=1;i<=x;i++)
{
for(j=1;j<=y;j++)
{
if(y*i==x*j)
{
printf("LCM is %d\n",y*i);
i=i+x;
}
}
}
getch();
}
OR
there will be another easy way to solve it...
Answer:
#include
#include
void main()
{
int x,y,i,;
clrscr();
printf("Enter Two Digits = ");
scanf("d",&x,&y);
for(i=1;i<=x*y;i++) {
if(i%x==0&&i%y==0)
{
printf(LCM is %d",i);
break;
}
}
getch();
}
Hey Friends here is the program of HCF and LCM with output:
Statement of C Program: Find The LCM and HCF of Two Numbers :
#include
void main()
{
int num1 , num2 , lcm , gcd , remainder , numerator , denominator ;
clrscr();
printf( "Enter two numbers\n");
scanf(" %d%d " , &num1 , &num2 );
if (num1 > num2)
{
numerator=num1;
denominator=num2;
}
else
{
numerator = num2 ;
denominator = num1 ;
}
remainder = num1 % num2;
while ( remainder != 0)
{
numerator = denominator;
denominator = remainder;
remainder = numerator % denominator;
}
gcd = denominator;
lcm = (num1 * num2 ) / gcd;
printf("GCD of %d and %d =%d\n" , num1, num2, gcd);
printf(" LCM of %d and %d= %d\n" , num1, num2, lcm);
getch();
}
Output:
Enter two numbers
5
15
GCD of 5 and 15 = 5
LCM of 5 and 15 = 15
01#include <iostream>
02using namespace std;
03
04
05int gcf(int a, int b ) {
06 int rem = a % b;
07 while (rem != 0){
08 rem = b % rem;
09 rem--;
10 return b;
11 }
12
13}
14
15
16int main () {
17
18 int x, y;
19 cout << "Enter two integers: ";
20 cin >> x >> y;
21
22 cout << "The greatest common factor of " << x << " and " << y
23 << " is " << gcf(x, y) << endl;
24
25 return 0;
26}
int gcd (int x, int y)
{
. if (x<0) x= -x;
. if (y<0) y= -y;
. if (x<y) { int tmp= x; x= y; y= tmp;}
. if (y==0) return x;
. else return gcd (y, x%y);
}
int LCM (int x, int y)
{
. int d;
. if (x<0) x= -x;
. if (y<0) y= -y;
. d= gcd (x, y);
. if (d==0) return d;
. else return x/d*y;
}
void lcm(int m,int n)
{
int i;
for(i=1;i++)
{
if(i%m==0&&i%n==0)
return i;
}
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