since at no load only excitation current(responsible for core loss ie iron loss) flow on the primary side so core loss current will be 1A and core loss = v1*i1*powerfactor. core loss = 1*11000*0.24= 2640watt.
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a 11000/400v distribution transformer takes no load primary currnt of 1a at a power factor of 0.24 lagging Find (1) core loss current (2) iron loss
Hysteresis and eddy current loss constitute core loss. It can be reduced by replacing solid core by laminated core... by adeeb
Yes the transformer effects the incoming frequency supply. This frequency is dependent on the core lamination of the transformer the weightier the core lamination the lesser will be the frequency we get and vice verse..
Iron losses (Pi) are independent of of load which occur due to pulsation of flux in the core. Iron losses include both Hysteresis loss and eddy current loss and is same at all the loads.
Yes, that is almost true, apart from a very small copper loss in the primary winding that carries the small magnetising current. The core loss (iron loss) depends on the applied voltage. This loss is measured by the open-circuit test, carried out at the working voltage.
t's basically a matter of the magnetizing inductive reactance which is inversely proportional to frequency. You want to keep the magnetizing current low to minimize power loss and avoid saturating the core. The higher the frequency, the lower the required inductance for a given inductive reactance and magnetizing current, thus the smaller the required core and/or number of turns on the windings.Magnetizing current is a normal parasitic byproduct of the transformer inductance and the applied voltage level and frequency. The amount of power that can be transferred through a transformer is usually limited by the transformer winding resistances and is unrelated to the magnetizing current. Thus core size goes up at higher power levels due to larger required wire size, not due to any core limitations.