In C++, it is better to use vectors than dynamic arrays because a vector always knows its own size. C-style arrays are better suited to static arrays where the size is always known in advance. The following demonstrates how a vector might be used within a class.
#include<iostream>
#include<vector>
class foo
{
public:
std::vector<int>& operator+= (int data){ m_data.push_back(data); return(m_data);}
int operator[] (size_t element)const{
ASSERT(element<m_array.size());
return( m_array[element]; }
const size_t size()const{return(m_data.size());}
private:
std::vector<int> m_data;
}
int main()
{
foo f;
f += 42;
f += 9;
for(int i=0; i<f.size(); ++i)
std::cout<<f[i]<<std::endl;
}
Output:
42
9
int array[10] = {...}; for (int i = 0; i < 10; ++i) { if (i % 2 == 0) array[i] += 5; else array[i] -= 10; }
The lowest subscript of an array in C, or C++ is 0.
If the array is static it can declared in the structure itself: struct myArrayTag { int num[12]; // array of 12 integers (e.g., 48 bytes). } myArray; If it is dynamic then you must use a pointer and allocate the array outside the structure. You should also maintain a variable in the structure to keep track of how many elements the array currently has: struct myBufferTag { int * array; // Pointer to array of integers. int size; // Size of array (number of elements); } myBuffer;
To determine if an array is symmetric, the array must be square. If so, check each element against its transpose. If all elements are equal, the array is symmetric.For a two-dimensional array (a matrix) of order n, the following code will determine if it is symmetric or not:templatebool symmetric(const std::array& matrix){for (size_t r=0 ; r
yes
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
int array[10] = {...}; for (int i = 0; i < 10; ++i) { if (i % 2 == 0) array[i] += 5; else array[i] -= 10; }
truzi i Ghal
The lowest subscript of an array in C, or C++ is 0.
Heres something i whipped up in a hurry... This uses the Bubble Sort method found (related links) #include <iostream> using namespace std; int main(int argc, const char* argv) { int arraysize = 5; //Unsorted array size int array [] = { 5, 3, 4, 2, 1 }; //The array of numbers itself //Display the unsorted array cout << "Before: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; //Acctually sort the array int tmp=0; //Used for swaping values for (int loop=0; loop <= (arraysize - 1); loop++) { for (int c=0; c <= (arraysize - 1); c++) //The sort loop { if (array[c] > array[c + 1]) { //Swaps the two values in the array tmp = array[c]; array[c] = array[c + 1]; array[c + 1] = tmp; //Cleanup tmp = 0; } } } //Display the sorted array cout << "After: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; return 0; }
If the array is static it can declared in the structure itself: struct myArrayTag { int num[12]; // array of 12 integers (e.g., 48 bytes). } myArray; If it is dynamic then you must use a pointer and allocate the array outside the structure. You should also maintain a variable in the structure to keep track of how many elements the array currently has: struct myBufferTag { int * array; // Pointer to array of integers. int size; // Size of array (number of elements); } myBuffer;
C++ array indices are zero-based because the first element in any array is offset 0 elements from the start address. The second element is offset by 1 element and the third by 2 elements, and so on. To put it another way, the index refers to the number of elements that come before the desired element. The first element has zero elements before it, so it is index 0. For an array of n elements, the last element is at index n-1.
Ah, honey, in C, you can get the number of elements in an array by dividing the total size of the array by the size of one element. So, if you have an array of integers, you can do something like int size = sizeof(array) / sizeof(array[0]); and voilà, you've got the number of elements. Just be careful with those pesky pointers and make sure you're not trying to count elements in a pointer instead of an actual array.
To determine if an array is symmetric, the array must be square. If so, check each element against its transpose. If all elements are equal, the array is symmetric.For a two-dimensional array (a matrix) of order n, the following code will determine if it is symmetric or not:templatebool symmetric(const std::array& matrix){for (size_t r=0 ; r
You cannot delete elements from an array. But you can move the elements: if (del_index < no_of_elements-1) { memmove (&array [del_index], &array [del_index+1], sizeof (array [0]) * (no_of_elements - del_index - 1)); } --no_of_elements;
array type
To get the size of an array in C, you can use the sizeof() operator. This operator returns the number of bytes occupied by the array, so to get the number of elements in the array, you can divide the total size by the size of one element.