In C++, it is better to use vectors than dynamic arrays because a vector always knows its own size. C-style arrays are better suited to static arrays where the size is always known in advance. The following demonstrates how a vector might be used within a class.
#include<iostream>
#include<vector>
class foo
{
public:
std::vector<int>& operator+= (int data){ m_data.push_back(data); return(m_data);}
int operator[] (size_t element)const{
ASSERT(element<m_array.size());
return( m_array[element]; }
const size_t size()const{return(m_data.size());}
private:
std::vector<int> m_data;
}
int main()
{
foo f;
f += 42;
f += 9;
for(int i=0; i<f.size(); ++i)
std::cout<<f[i]<<std::endl;
}
Output:
42
9
int array[10] = {...}; for (int i = 0; i < 10; ++i) { if (i % 2 == 0) array[i] += 5; else array[i] -= 10; }
The lowest subscript of an array in C, or C++ is 0.
If the array is static it can declared in the structure itself: struct myArrayTag { int num[12]; // array of 12 integers (e.g., 48 bytes). } myArray; If it is dynamic then you must use a pointer and allocate the array outside the structure. You should also maintain a variable in the structure to keep track of how many elements the array currently has: struct myBufferTag { int * array; // Pointer to array of integers. int size; // Size of array (number of elements); } myBuffer;
To determine if an array is symmetric, the array must be square. If so, check each element against its transpose. If all elements are equal, the array is symmetric.For a two-dimensional array (a matrix) of order n, the following code will determine if it is symmetric or not:templatebool symmetric(const std::array& matrix){for (size_t r=0 ; r
If this is a homework related question, you really should consider trying to solve it yourself before looking at this answer. Otherwise, the value of the lesson, and the reinforcement provided by the assignment, will be lost to you. You do not create individual elements of arrays in C or C++. You create the array, and then reference the elements. Say you want to create a 10 x 20 array of floats. You would declare float MyFloatArray[10][20]. You would then reference the elements, such as MyFloatArray[3][8]. Note that 10 and 20 are the number of elements in each direction, but the valid range of indices is 0 to 9 and 0 to 19, respectively.
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
int array[10] = {...}; for (int i = 0; i < 10; ++i) { if (i % 2 == 0) array[i] += 5; else array[i] -= 10; }
truzi i Ghal
The lowest subscript of an array in C, or C++ is 0.
Heres something i whipped up in a hurry... This uses the Bubble Sort method found (related links) #include <iostream> using namespace std; int main(int argc, const char* argv) { int arraysize = 5; //Unsorted array size int array [] = { 5, 3, 4, 2, 1 }; //The array of numbers itself //Display the unsorted array cout << "Before: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; //Acctually sort the array int tmp=0; //Used for swaping values for (int loop=0; loop <= (arraysize - 1); loop++) { for (int c=0; c <= (arraysize - 1); c++) //The sort loop { if (array[c] > array[c + 1]) { //Swaps the two values in the array tmp = array[c]; array[c] = array[c + 1]; array[c + 1] = tmp; //Cleanup tmp = 0; } } } //Display the sorted array cout << "After: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; return 0; }
If the array is static it can declared in the structure itself: struct myArrayTag { int num[12]; // array of 12 integers (e.g., 48 bytes). } myArray; If it is dynamic then you must use a pointer and allocate the array outside the structure. You should also maintain a variable in the structure to keep track of how many elements the array currently has: struct myBufferTag { int * array; // Pointer to array of integers. int size; // Size of array (number of elements); } myBuffer;
C++ array indices are zero-based because the first element in any array is offset 0 elements from the start address. The second element is offset by 1 element and the third by 2 elements, and so on. To put it another way, the index refers to the number of elements that come before the desired element. The first element has zero elements before it, so it is index 0. For an array of n elements, the last element is at index n-1.
To determine if an array is symmetric, the array must be square. If so, check each element against its transpose. If all elements are equal, the array is symmetric.For a two-dimensional array (a matrix) of order n, the following code will determine if it is symmetric or not:templatebool symmetric(const std::array& matrix){for (size_t r=0 ; r
You cannot delete elements from an array. But you can move the elements: if (del_index < no_of_elements-1) { memmove (&array [del_index], &array [del_index+1], sizeof (array [0]) * (no_of_elements - del_index - 1)); } --no_of_elements;
array type
If this is a homework related question, you really should consider trying to solve it yourself before looking at this answer. Otherwise, the value of the lesson, and the reinforcement provided by the assignment, will be lost to you. You do not create individual elements of arrays in C or C++. You create the array, and then reference the elements. Say you want to create a 10 x 20 array of floats. You would declare float MyFloatArray[10][20]. You would then reference the elements, such as MyFloatArray[3][8]. Note that 10 and 20 are the number of elements in each direction, but the valid range of indices is 0 to 9 and 0 to 19, respectively.
yes