An array is simply a contiguous block of memory that is divided into one or more elements of equal size. The array name is itself a reference to the start address of the array, which has the same address as the first element in the array (the element with index 0). The index is essentially an offset from the start of the array, multiplied by the size of an element. However, there is no built-in mechanism in C to prevent you from accessing elements beyond the upper bound of the array at runtime -- essentially overflowing the array. Since C++ inherits from C, the same problem exists in C++. For instance, in a 10 element array, the upper bound is 9. If you attempt to write to element 10, you are overflowing the array, the buffer, because that memory does not belong to the array. You then introduce undefined behaviour. At best, nothing bad will happen. At worst, people could die. Once you introduce undefined behaviour there's simply no telling what could happen -- it's a time-bomb waiting to go off. The only way to avoid such problems is to ensure all your array offsets remain within the bounds of the array. That is, the onus is upon the C++ programmer -- just as it still is with the C programmer.
The lowest subscript of an array in C, or C++ is 0.
#include main() { int array[100], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) { minimum = array[c]; location = c+1; } } printf("Minimum element is present at location number %d and it's value is %d.\n", location, minimum); return 0; }
No, it is not allowed to exceed the allocated size of an array. However, few compilers check, so if the programmer fails to check, he or she can get in trouble, by corrupting other memory or throwing a bus exception.
Wright a 'C' program for storage representation of 2-D array.
An array is simply a contiguous block of memory that is divided into one or more elements of equal size. The array name is itself a reference to the start address of the array, which has the same address as the first element in the array (the element with index 0). The index is essentially an offset from the start of the array, multiplied by the size of an element. However, there is no built-in mechanism in C to prevent you from accessing elements beyond the upper bound of the array at runtime -- essentially overflowing the array. Since C++ inherits from C, the same problem exists in C++. For instance, in a 10 element array, the upper bound is 9. If you attempt to write to element 10, you are overflowing the array, the buffer, because that memory does not belong to the array. You then introduce undefined behaviour. At best, nothing bad will happen. At worst, people could die. Once you introduce undefined behaviour there's simply no telling what could happen -- it's a time-bomb waiting to go off. The only way to avoid such problems is to ensure all your array offsets remain within the bounds of the array. That is, the onus is upon the C++ programmer -- just as it still is with the C programmer.
A string in C is stored in a 1 dimension array so an array of strings is simply a two dimension array.
The lowest subscript of an array in C, or C++ is 0.
Heres something i whipped up in a hurry... This uses the Bubble Sort method found (related links) #include <iostream> using namespace std; int main(int argc, const char* argv) { int arraysize = 5; //Unsorted array size int array [] = { 5, 3, 4, 2, 1 }; //The array of numbers itself //Display the unsorted array cout << "Before: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; //Acctually sort the array int tmp=0; //Used for swaping values for (int loop=0; loop <= (arraysize - 1); loop++) { for (int c=0; c <= (arraysize - 1); c++) //The sort loop { if (array[c] > array[c + 1]) { //Swaps the two values in the array tmp = array[c]; array[c] = array[c + 1]; array[c + 1] = tmp; //Cleanup tmp = 0; } } } //Display the sorted array cout << "After: {"; for (int c=0; c <= arraysize; c++) { cout << array[c]; if (c != arraysize) { cout << ","; } } cout << "}" << endl; return 0; }
ali asghari: I would say that the lack of bounds checking in array access would qualify. Bounds checking incurs a lot of overhead which is not needed in a properly written program. C is designed with the idea that one has to trust the programmer. If the programmer thinks that a bounds check is needed he must explicitly program it everywhere he accesses the array. This is one of the advantages of C++ objects where a single bounds check can be made in the array access methods as well as allowing for non-bounds-checked access.
You cannot add elements to a fixed array in C or C++. If, however, the array is declared as a pointer to an array, you can add elements by allocating a new array, copying/adding elements as needed, reassigning the new array to the pointer, and deallocating the original array.
The syntax to access a particular element in an array are the same in both languages: For example: assume array is an array of 10 int(egers): to get the first element: array[0] (both are 0 based indexing] int i = 0; while (i < array.Length) { // do something to array[i] } int i = 0; int length = sizeof(array) / sizeof(int); while (i < length) { // do something to array[i] } However, an array in C# is also enumerable (C does not have this feature) in C#, you may loop thru the array by: foreach (int number in array) { // do something to array[i] } Plus, C# is an Object-Oriented Language, so that an array may be of some object types, not just those primitiives data types in C: object[] objectArray; // any object derived from Object may be placed into objectArray, not just struct. In another variation, an array may be of Delegate type in C#(sort of like function pointers in C)
If the array consists of r rows and c column, and the total number of cells in the array are n = r*c, then r*c = n and c*r = n so that r*c = c*r : which is commutativity of multiplication.
#include main() { int array[100], minimum, size, c, location = 1; printf("Enter the number of elements in array\n"); scanf("%d",&size); printf("Enter %d integers\n", size); for ( c = 0 ; c < size ; c++ ) scanf("%d", &array[c]); minimum = array[0]; for ( c = 1 ; c < size ; c++ ) { if ( array[c] < minimum ) { minimum = array[c]; location = c+1; } } printf("Minimum element is present at location number %d and it's value is %d.\n", location, minimum); return 0; }
cod a program student degree array in c language
No, it is not allowed to exceed the allocated size of an array. However, few compilers check, so if the programmer fails to check, he or she can get in trouble, by corrupting other memory or throwing a bus exception.
No.