THINK! (famous sign used in IBM for decades to motivate employees)
What would happen if an ideal voltage source (i.e. no internal resistance) was connected directly across a diode in the forward bias direction? For a real silicon diode the knee voltage is about 0.7V and the diode's internal resistance can drop roughly another 0.3V before overloading. If the voltage source applied more than the sum of the knee voltage and the maximum voltage the internal resistance can drop before overloading (this sum is roughly 1V) then bad things will happen.
You should have been able to figure out you answer yourself from the above. The situation above is only trivially changed by the use of a real voltage source (i.e. having internal resistance), it only postpones the overload a little.
If diode is connected in series then current will flow only in one direction. ie. Current flow occurs only when diode is forward biased. ANSWER: It depends are the diodes are connected in series if they are back to back no current will flow if connected in the forward conduction mode then they will conduct.
The dynamic resistance of a diode, be it zener or otherwise, will be different from its static resistance because a diode is not a resistor, and resistance is not a function of current flow. It is a diode, and a diode has its own characteristic voltage to current curve, forward and, in the case of a zener, reverse.
when a diode is forward biased it conducts current
there is no forward breakdown voltage for any diode
you could use a current limiting diode such as a Zenner, or a current limiting resistor in series with the LED
A series resistor is necessary when a diode is forward-biased to limit the current flowing through the diode and prevent damage to the diode. Without a series resistor, the diode could draw excess current and overheat, potentially causing it to fail. The resistor helps control the current and protect the diode in the circuit.
Consider ideal diode to be connected in series with resistor of 6kSilicon diode forward bias voltage = 0.7 voltsCurrent across 6k resistor = (5-0.7)/6000 amperesVoltage across {resistor + diode}=4.3 + 0.7=5vIf silicon internal resistance is 6k then voltage across diode=5vIf external resistance is 6k and diode resistance is negligible then voltage across diode=0.7v
The junction (diode or transistor) will be destroyed.
If diode is connected in series then current will flow only in one direction. ie. Current flow occurs only when diode is forward biased. ANSWER: It depends are the diodes are connected in series if they are back to back no current will flow if connected in the forward conduction mode then they will conduct.
you should specify: - circuit topology, I assume a series connection. - diode allows current flow? It depends how it's connected - diode forward voltage drop value if diode is in forward conduction, you have VR=10V - VDIODE and, thus, I = VR/R=(10-Vdiode)/1200.
There isn't anything "scientific" about this simple series circuit. If you've got a variable resistor (a potentiometer) and a diode in series, you have a simple series circuit with the two components in it.
The resistor limits current so you can measure voltage across the diode. When you forward bias and saturate a junction, the voltage across it will be constant (0.7 in silicon, for example).
The diode voltage drop is 0.7 volts, so you need that much to turn it on. Current is controlled by a resistor in series.
No... Diode block one way... resistor block eitherway.
An inductor will supply better current source.
The dynamic resistance of a diode, be it zener or otherwise, will be different from its static resistance because a diode is not a resistor, and resistance is not a function of current flow. It is a diode, and a diode has its own characteristic voltage to current curve, forward and, in the case of a zener, reverse.
Germanium diodes typically have a forward voltage drop of around 0.3V. This means that the diode will start conducting current when a voltage of around 0.3V is applied across it in the forward direction. It is lower than the forward voltage drop of silicon diodes, which is usually around 0.6-0.7V.