Because it has to be 1 when the phase angle is zero.
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mw is the unit of real power and mvar is unit of reactive power. You should now the current and power factor angle to calculate the voltage.p=vi cos piq=vi sin piAnswerI think you mean MW, not mw -capital 'M' mega; lower-case 'm' milli!!! And the symbol for watt is a capital 'W', not a lower case 'w'. Also, I think you mean 'Mvar'(mega, not milli!).
Q = 3 Vph Iph sin(phase angle) = 31/2 Vline Iline sin(phase angle)
The defination of form factor is FF=RMS/avg(abs(f(t))) for sin waveform RMS=0.707*peak(f) avg(abs(f(t)))=2/pi*peak(f) so FF=0.707/(2/pi)=1.1106
This is a simple derivation problem. Take the derivative of the AC voltage waveform (I'll assume sin (t)), and set the derivative equal to the maximum value it can attain (which is 1): cos (t) = 1, t = 0 degrees, thus for an AC waveform of y = sin(t), the fastest increase in voltage occurs at 0, 360, etc. degrees. The fastest decrease in voltage will occur at 180, 180 + 360, etc. degrees.
kvar = kva*sin@