There may be an "open neutral" somewhere either in your breaker panel or in the meter base.
Contact a qualified electrician to help solve the problem. An open neutral causes one leg of the electrical service to be "low" voltage, while the other leg goes "high". That can result in premature failure of electrical components, such as light bulbs, electronic devices and electric motors.
Output from secondary is about 6.8V rms, on no load. On the primary side, you have 140 / 120 = .86 volts per turn. Therefore, on the secondary side you will have 8*.86 = 6.8 volts.
86
If a cable insulation is described as RHW, you would be able to use the cable for what maximum temperature? A. 194°FB. 140°FC. 86°FD. 167°F
Tesla died penniless at age 86 on January 7, 1943. In his lifetime, he received over 800 different patents. Scientists continue to scour through his notes.
To answer this question, wire size is rated in the amount of amperage that it can legally carry. Fuse sizing is based on the amperage that the wire carries. The formula to find amperage when the HP is known is I = HP x 746/1.73 x E x %eff x pf. A standard motor's efficiency between 5 to 100 HP is .84 to .91. A standard motor's power factor between 10 to 100 HP is .86 to .92. Amps = 30 x 746 = 55950 = 55950/ 1.73 x 415 x .87 x .87 = 55950/550 = 101 amps. The electrical code states that a motor conductor has to be rated at 125% of the motors full load amperage. 101 x 125% = 126 amps A #2 copper conductor with an insulation factor of 90 degrees C is rated at 130 amps. Fusing for this motor will be, non time delay fuse 300 amps, time delay fuse 175 amps or a circuit breaker rated at 250 amps.
86% of 120 is 103.2
There are 1 times 86 in 120. The answer you divide 120 by 86 which would get you 1.3953488372093. The remainder is 34 Similar Questions With Same Answer = 1.3953488372093.
Output from secondary is about 6.8V rms, on no load. On the primary side, you have 140 / 120 = .86 volts per turn. Therefore, on the secondary side you will have 8*.86 = 6.8 volts.
Output from secondary is about 6.8V rms, on no load. On the primary side, you have 140 / 120 = .86 volts per turn. Therefore, on the secondary side you will have 8*.86 = 6.8 volts.
71.67%
8 + 6 = 14 and 40 + 80 = 120. So therefore 48 + 86 = 14 + 120 which is 134
39.5349% increase.
72% is usually a C minus.
7 + 21 + 2 + 86 + 4 = 120
86 students, 34 teachers pop: 120
You can power an 86 volt light with a power source that outputs 86 volts, such as a specific battery or power supply designed for that voltage. Ensure that the power source can provide enough current to safely operate the light without damaging it.
It could be 97 which is a prime number.