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Why are NAND gates cheaper to make than others?

Anonymous

∙ 12y ago

Updated: 4/28/2022

Because they are universal, which means you can build entire circuits out of only NAND or NOR gates, instead of combinations of OR, AND and the other gates. As a result, companies buy bulks of NAND gates to save money, because ordering one thing in huge numbers will always be cheaper than buying various things at the same number for the manufacture.

Wiki User

∙ 12y ago

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Minimum number of nand gates required to form full and half adder?

Check this link http://www.dumpt.com/img/viewer.php?file=bd6b3mqsa66fhr6c76l1.bmp

What are the advantages of universal logic gates?

THE MAIN ADVANTAGE OF THE UNIVERSAL LOGIC GATES IS THAT IT CAN BE USED TO MADE ANT KIND OF LOGIC GATE .......BY USING IT . NAND AND NOR ARE CALLED AS UNIVERSAL GATES ARE USED TO MAKE ANY GAATES AS OR ,AND, XNOR,NOT. logic gates are used in many everyday electronic devices such as tv's, computers and telephones.

How many 2-input and gates can replace n-input and gate Does that apply for nand gates as well?

for a two input gate to represent as an n-input gate excatly n-1 two input gates are required. this implies that for a two input OR gate to represent a four input OR gate exactly three two input OR gates are required let F is =a+b+c+d =(((a+b)+c)+d) =((a+b)+(c+d)) in both the above cases + is used three times so three two input OR gates make a four input OR gates. This discussion doesnot hold good for NAND gates an example can illlustrate the reson:- take F=(a.b.c.d)'=a'+b'+c'+d' --------------------------->(1) (this is obtained by a four input NAND gate) let us take this in the manner we did it for an OR gate and we will then verify the result. =((a.b)'(c.d)')' =((a'+b').(c'+d'))' =(a'+b')'+(c'+d')' =ab+cd <------------------------(2) (1)is not equal to (2) so we can say that a NAND gate cannot be replaced in the manner as OR gate is replaced

Full subtractor circuit using x-or gate?

To make a full subtractor, you need an XOR and a NAND gate.

How many XNOR gates does it take to make a 4 bit binary comparator?

4

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Related Questions

How many gates you can make using universal gates?

Seven gates, they are: not, and, or, nor, nand, xor, xnor.

Is nand gate a universal gate?

NAND AND NOR gates are called universal gates , becaus with a combination NAND and NOR gates alone, it's possible to create all other logic gates like AND, OR, XOR etc and you can design any logic circuit. eg: inverter-- nand with inputs shorted. and ------ nand followed by a inverter(using nand). or--------- giving inverted inputs to nand gate.

Minimum number of nand gates required to form full and half adder?

Check this link http://www.dumpt.com/img/viewer.php?file=bd6b3mqsa66fhr6c76l1.bmp

How nand gate acts as a universal gate?

A universal gate is a gate which can implement any Boolean function without need touse any other gate type.The NAND and NOR gates are universal gates.In practice, this is advantageous since NAND and NOR gates are economical andeasier to fabricate and are the basic gates used in all IC digital logic families.In fact, an AND gate is typically implemented as a NAND gate followed by aninverter not the other way around!!Likewise, an OR gate is typically implemented as a NOR gate followed by an inverternot the other way around!!A universal gate is a gate which can implement any Boolean function without need touse any other gate type.The NAND and NOR gates are universal gates.In practice, this is advantageous since NAND and NOR gates are economical andeasier to fabricate and are the basic gates used in all IC digital logic families.In fact, an AND gate is typically implemented as a NAND gate followed by aninverter not the other way around!!Likewise, an OR gate is typically implemented as a NOR gate followed by an inverternot the other way around!!can be combined to produce AND, OR,NOT,XORand XNOR gates

What is universal logic gate?

universal logic gate is a gate using which you can make all the logic gates there are two such gates NOR gate and NAND gate

What are the components required to make calculator?

There are several components required to make a calculator. These include the lattice brevia, a box of nand gates, and a micro-controller.

How do you design 1-bit half adder with NAND gates only?

As this is obviously a homework problem, I won't answer it. However I will give you couple of hints. First figure out how to make an exclusive-or gate from nand gates. The rest is trivial. Using a Karnaugh map will make it much simpler to design than using an ordinary truth table.

What Are The Advantages Of Universal Gates?

THE MAIN ADVANTAGE OF THE UNIVERSAL LOGIC GATES IS THAT IT CAN BE USED TO MADE ANT KIND OF LOGIC GATE .......BY USING IT . NAND AND NOR ARE CALLED AS UNIVERSAL GATES ARE USED TO MAKE ANY GAATES AS OR ,AND, XNOR,NOT. logic gates are used in many everyday electronic devices such as tv's, computers and telephones.

What are the advantages of universal logic gates?

THE MAIN ADVANTAGE OF THE UNIVERSAL LOGIC GATES IS THAT IT CAN BE USED TO MADE ANT KIND OF LOGIC GATE .......BY USING IT . NAND AND NOR ARE CALLED AS UNIVERSAL GATES ARE USED TO MAKE ANY GAATES AS OR ,AND, XNOR,NOT. logic gates are used in many everyday electronic devices such as tv's, computers and telephones.

What are the Advantage of universal gate?

THE MAIN ADVANTAGE OF THE UNIVERSAL LOGIC GATES IS THAT IT CAN BE USED TO MADE ANT KIND OF LOGIC GATE .......BY USING IT . NAND AND NOR ARE CALLED AS UNIVERSAL GATES ARE USED TO MAKE ANY GAATES AS OR ,AND, XNOR,NOT. logic gates are used in many everyday electronic devices such as tv's, computers and telephones.

How many 2-input and gates can replace n-input and gate Does that apply for nand gates as well?

for a two input gate to represent as an n-input gate excatly n-1 two input gates are required. this implies that for a two input OR gate to represent a four input OR gate exactly three two input OR gates are required let F is =a+b+c+d =(((a+b)+c)+d) =((a+b)+(c+d)) in both the above cases + is used three times so three two input OR gates make a four input OR gates. This discussion doesnot hold good for NAND gates an example can illlustrate the reson:- take F=(a.b.c.d)'=a'+b'+c'+d' --------------------------->(1) (this is obtained by a four input NAND gate) let us take this in the manner we did it for an OR gate and we will then verify the result. =((a.b)'(c.d)')' =((a'+b').(c'+d'))' =(a'+b')'+(c'+d')' =ab+cd <------------------------(2) (1)is not equal to (2) so we can say that a NAND gate cannot be replaced in the manner as OR gate is replaced

How can you make nand gate from and gate?

A nand gate can be made from an and gate by introducing an inverter at the output of the gate.

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