that is to reduce the cost of the power plant....
Improving power factor(increasing the ration active/apparant power morethan 0.8) will increase the efficiency of uer system. Improving power factor denotes eleminating the recative power(which do no average work).... If u have more capacitive parts in uer system, the power you may need be really high when the capacitor is charging. But as it is in an a.c. system, used energy will be released and hence the average energy consumption of the cap is null. As in one instance iot absorbes energy, the electricity distributers must be able to generate such an high power which will incrrease their cost(eventhough the absorbed energy will be released)!!!
Just by reducing the the reactive power, you can reduce the enery absorption. However to do so, you may have to use caps/inductors whcich will cost you a lot.
Generally, electricity distributors say, "You must not reduce uer power factor than 0.8"... In some countries, distributors pay for the factries if there power factor is higher than a cirtain value(0.95)....
-R-
the series LC circuit without significant R in the series connection may lead to a resonant current. The term is usually called ferroresonance.
The frequency can be dependent on any harmonic currents in the transformer load. A transformer iron core stores energy and switching/harmonic currents allow the energy to be transferred in part as current flowing to charge the load capacitors. The rapid charging of the capacitor will cause a severe over voltage,
failure does occur.
regards,
grahame Arnold
The power in a 15 MVA (15000 KVA) transformer depends on the power factor. You did not specify the power factor, so I will assume a power factor of 0.92. Simply multiply MVA by PF and you get 13.8 MW.
The inductance of the transformer is much higher than the resistance of the transformer, resulting in very low real power losses (in watts), but some reactive power (vars).
transformer action doesn't depend on power factor that is why we indicate its rating in KVA
When it supplies a resistive load.
There is no such thing as a 'low power-factor' wattmeter. A wattmeter always reads true power, regardless of the load's power factor.
When its load has a leading power factor.
zero volatge regulation means the terminal volatge of transformer at full load on a given power factor become equal to the rated teriminal volatge of transformer , it happens only for leading power factor in transformer
It isn't! A transformer operating at no load has a very low power factor.
The power factor is only taken into consideration when the Kilowatts of a transformer is used.
The power in a 15 MVA (15000 KVA) transformer depends on the power factor. You did not specify the power factor, so I will assume a power factor of 0.92. Simply multiply MVA by PF and you get 13.8 MW.
In generator station the power which produced is real power the real power to me mentioned in its's factor so it is mentioned as KW or MW. In transformer there is no effect of change the power factor (ie:cos,phi) and the power which transfer do not changes its frequency. so, in Transformer and generator it is mentioned as KVA.
The kW rating of a transformer can be calculated by multiplying the kVA rating by the power factor. For example, if the power factor is 0.8, then the kW rating of a 100 kVA transformer would be 80 kW. You can also use the formula: kW = kVA x power factor.
The inductance of the transformer is much higher than the resistance of the transformer, resulting in very low real power losses (in watts), but some reactive power (vars).
transformer action doesn't depend on power factor that is why we indicate its rating in KVA
yes there is
When it supplies a resistive load.
There is no such thing as a 'low power-factor' wattmeter. A wattmeter always reads true power, regardless of the load's power factor.