peak value =rms value*1.414 =220*1.414 =311v
Chat with our AI personalities
You can work this out yourself. For a sinusoidal waveform the rms value is 0.707 times the peak value. As you quote a peak-to-peak value, this must be halved, first. Incidentally, the symbol for volt is 'V', not 'v'.
All a.c. voltages are expressed in root-mean-square (r.m.s.) values, unless otherwise stipulated. So 12 V is an r.m.s value which, for a sinusoidal waveform, has an amplitude, or peak value, of 1.414 x 12 = 16.97 V. So its peak-to-peak value will be twice this amount -i.e. 33.94 V.
For a sine wave ONLY - and assuming you are talking plus and minus 100V (200V peak to peak) - the RMS voltage is about 71V. (One half square root of 2 * single sided peak value)
ANSWER: The peak to peak voltage can be found by multiplying 120 v AC x 2.82= 339.41
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.