Resistance is a completely different quantity to capacitance, resistance being measured in ohms and capacitance in farads. So they are 'apples and Oranges'. You should be asking, 'What happens if capacitive reactance (in ohms) is larger than resistance?'. And one answer would be that the phase angle will be greater than 45 degrees. There are other answers, too, but it depends what you want to know,
The series resistance (swamping resistance and multiplier) in pressure coil circuit has many turns.So in addition to inductance seen before, there are inter-turn capacitance also.If this capacitance effect exceeds the inductance effect, a phase-shift in pressure coil current will cause an error.When pressure coil capacitance roughly equals the inductance, the errors cancel each other.In most cases the inductance is more than the capacitance and thus the shunting capacitor mentioned before will serve the purpose.
A preset resistor is used in some circuits to change the resistance. The preset resistor enables the circuit to be more or less sensitive thereby altering the resistance.
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.
to determine the comparison of resistance value of both forward and reverse diode . The more the resistance the lower the current , the lower the resistance the higher the current . When reverse bias , the resistance is high and it acts in open circuit and the reverse current is very small that can be neglected . When forward bias , the resistance is low and it acts as short circuit and the forward current is increasing as the voltage supply is higher .
yes because of bulb resistance :)
The reciprocal of capacitance is elastance. This is perhaps more convenient for circuit analysis than capacitance. In a circuit, a capacitor can be neglected if the elastance is set to zero. In the same way, a resistor/inductor can be ignored if its resistance/inductance is set to zero.
You need to be little more specific to get an accurate answer. Capacitance in which circuit? Thanks.
First, capacitance is the resistance of something to a change in voltage. And capacitance exists anywhere there is a conductor that is insulated from another conductor. With that definition, anything has capacitance. And that's correct. It is also the key to understanding the capacitance in high frequency (radio frequency or RF) circuits. The fact that a circuit had conductive pathways and component leads and such means that there is a lot of little bits of capacitance distributed around the circuit. The capacitance is already there; it isn't "added" later as might be inferred. Normally, this bit of capacitance isn't a problem. But at higher and higher frequencies, it is. Remember that the higher the frequency of an AC signal, the better it goes through a given cap. So at higher and higher frequencies, the distributed capacitance in the circuit "shorts the signal to ground" and takes it out of the circuit. The RF is said to be coupled out of the circuit through the distributed capacitance in that circuit. The higher the frequency a given circuit is asked to deal with, the more signal will be lost to this effect. It's just that simple. Design considerations and proper component selection minimize the distributed capacitance in a circuit.
When more light bulbs are added in parallel to a circuit, the total resistance of the circuit decreases. This is because in a parallel circuit, the reciprocal of the total resistance is equal to the sum of the reciprocals of the individual resistances. More paths for current to flow mean less overall resistance in the circuit.
The series resistance (swamping resistance and multiplier) in pressure coil circuit has many turns.So in addition to inductance seen before, there are inter-turn capacitance also.If this capacitance effect exceeds the inductance effect, a phase-shift in pressure coil current will cause an error.When pressure coil capacitance roughly equals the inductance, the errors cancel each other.In most cases the inductance is more than the capacitance and thus the shunting capacitor mentioned before will serve the purpose.
Adding more branches to a parallel circuit decreases the overall resistance of the circuit. This leads to an increase in the total current flowing through the circuit as each branch provides an additional pathway for the current to flow. This results in a decrease in the total resistance and an increase in the overall current of the circuit.
Resistance goes up creating more heat which eventually leads to an open circuit.
This happens only in pure series circuits, due to increased resistance.
If you add more loads to a series circuit, the overall resistance in the circuit increases, which decreases the overall current flowing through the circuit. This can result in a decrease in the brightness of light bulbs or a decrease in the speed of motors connected in the circuit.
A capacitor is composed of two conductors that are separated by an insulator. This is a simple definition, but it says a lot about capacitance, and it says it very well. By this definition, there could be capacitance just about anywhere in a power system or circuit. Yes! There could! And there is! Capacitance offers "resistance" to alternating current (AC) signals called reactance. The higher the frequency, the less reactance there is and the better the signal will be able to pass through the capacitor. In modern electronic equipment, there are lots of circuit pathways and lots of components in the circuits. This leads to a lot of distributed capacitance in the circuit. This distributed capacitance represents a lot of little pathways for signals to "jump gaps" in the circuit. Signals will avoid going through the components and devices and also avoid following all the pathways it is supposed to follow. The signals will be "shorted around" components or "shorted to ground" in other pathways. This combines to effect signal loss or degradation. The higher the frequency of the signal put through a circuit, the more loss there will be to the signal due to distributed capacitance.
When you have multiple loads in a series, the resistance of the loads is added together allowing very little current to flow through the circuit to power any of the loads, making for a low amperage circuit. If you have your loads in parellel, the resistance of the loads in the circuit is subtracted which allows more current to flow, making for a high amperage circuit.
Current decreasesWhen voltage remains constant and resistance increases the current in the circuit will reduce.More informationV=IRwhere V is voltage,I is current andR is resistance.From the above equation,R=V/I, and hence resistance is indirectly proportional to current.Therefore, an increase in resistance would have the effect of decreased current.NB: this holds true only as long as the voltage remains constant.Another opinionHowever, this is only true in the case of a circuit connected in series.When circuits are connected in parallel, the opposite happens. If there is an increase in the amount of resistors in parallel, the total resistance of the circuit then decreases and the current increases subsequently.Yet another viewNo, that's not stated right.If more resistors are added in parallel - so that the circuit's overall total resistance decreases and its total current increases - that is NOT in any way the opposite of what this question is asking about...Let's make this crystal clear, so that there is no confusion: "an increase in the amount of resistors" is NOT the same as "an increase in resistance".So a parallel circuit behaves EXACTLY the same as a series circuit: if its overall resistance increases, the overall current going through the parallel circuit decreases AND if its overall resistance decreases, the overall current going through the parallel circuit increases.Actually, the second opinion is correctIn a parallel circuit, there are more branches to allow electrons back to the power supply, so current increases. With more resistors in a circuit, the overall resistance in a parallel circuit DECREASES.In a series circuit, current is the same throughout. So if more resistors are added, resistance INCREASES and so current DECREASES.