If the resistance is in series with the capacitor, the charge/discharge time is extended.
The time constant is equivalent to 1/(R*C); since C (the capacitance of the capacitor) is not changing, yes, the charging and discharging times will be the same, provided the Thevenin resistance is the same as well - if you charge a capacitor using a AA battery, then remove the battery, and discharge through a resistor, you have changed the Thevenin resistance, thus the discharge time will NOT be equal.
The C represents the capacitance (in farads) of the capacitor. It is a measure of how much charge a capacitor can hold. This is needed to know how much energy the capacitor is holding.
The charging and discharge time increases. R*C=T
A resistor is used to limit current flow through a capacitor.If you did not use the resistor, you could potentially create large currents through the capacitor, damaging it. Capacitors do have current limit ratings - check the specification sheet for the capacitor.Also, in the case of an electrolytic capacitor, if it is generally in a discharged state then it is necessary from time to time to reform it. That process involved slowly charging it, i.e. through a resistor, and then letting it discharge by itself with no or little load. The resistor protects both the capacitor and the voltage source in the case that the capacitor might be shorted.
The product of resistance and capacitance is referred to as the time constant. It determines rate of charging and discharging of a capacitor.
If the resistance is in series with the capacitor, the charge/discharge time is extended.
Capacitor is nothing but a storage device. It has a dielectric media in between the two electrodes. the nature of the capacitor is charging and discharging the voltage.
In the experiment of flashing and quenching of a capacitor, the neon bulb twinkles because the charging and discharging of the capacitor cause the voltage across the capacitor to fluctuate rapidly. These fluctuations can cause the neon bulb to turn on and off, leading to the twinkling effect.
No, the time constant is different for discharging and charging capacitors. The time constant for charging a capacitor is given by the product of the resistance and capacitance (Ο = RC), while for discharging it is given by the product of the resistance and the remaining capacitance (Ο = RC).
The charging time of a capacitor is usually lower than the discharging time because during charging, the voltage across the capacitor is increasing from zero to its maximum value, which initially allows a higher current to flow. During discharging, the voltage across the capacitor is decreasing from its maximum value to zero, resulting in a lower current flow. This difference in current flow affects the time it takes for the capacitor to charge and discharge.
using CRO we can measure the rise time and fall time of the capacitor for further studies
because of charging and discharging of capacitor present in the circuit. beacause capacitor charges exponentially. akshay dabhane
The time constant is equivalent to 1/(R*C); since C (the capacitance of the capacitor) is not changing, yes, the charging and discharging times will be the same, provided the Thevenin resistance is the same as well - if you charge a capacitor using a AA battery, then remove the battery, and discharge through a resistor, you have changed the Thevenin resistance, thus the discharge time will NOT be equal.
capacitor's characteristic is charging and discharging. discharged energy will be dropped by load . so it is connected in parallel
in the capacitor they have constant voltage wen supply is given the capacitor get charged(high voltage)and discharge energy wen the voltage is low below the applied voltag.
ac passes by repeatedly charging and discharging the capacitor. when you study ac circuit analysis, you will find out about impedance and reactance, which will allow you to compute how ac behaves in capacitors and inductors.