Sixteen. One bit per flip flop. A flip flop can represent only a true or a false. You need sixteen of these (1's and 0's) to make sixteen bits.
It can be seen that the external clock pulses (pulses to be counted) are fed directly to each J-K flip-flop in the counter chain and that both the J and K inputs are all tied together in toggle mode, but only in the first flip-flop, flip-flop A (LSB) are they connected HIGH, logic "1" allowing the flip-flop to toggle on every clock pulse. Then the synchronous counter follows a predetermined sequence of states in response to the common clock signal, advancing one state for each pulse. The J and K inputs of flip-flop B are connected to the output "Q" of flip-flop A, but the J and K inputs of flip-flops C and D are driven from AND gates which are also supplied with signals from the input and output of the previous stage. If we enable each J-K flip-flop to toggle based on whether or not all preceding flip-flop outputs (Q) are "HIGH" we can obtain the same counting sequence as with the asynchronous circuit but without the ripple effect, since each flip-flop in this circuit will be clocked at exactly the same time. As there is no propagation delay in synchronous counters because all the counter stages are triggered in parallel the maximum operating frequency of this type of counter is much higher than that of a similar asynchronous counter. Type your answer here...
a 2 bit counter is a counter which have only 2 bits i.e. the posibble counting states are 00, 01, 10,11,00. It may also be known as MOD 3 counter. It can be realized by using 2 Flip flop.
Designing a 3 bit synchronous counter using jk flip flop is not an easy project for the uninformed. This is best left to professionals who are adept at programming. There are lengthy guides available on the internet if it is necessary to create one.
one bit in two output states true or false
The parallel counter incorporates carry lookahead circuits so that all flip-flops in the counter change in sync with the clock pulse. The ripple counter each flip-flop output is the clock for the next flip-flop, causing the most significant bit of the counter to settle only after a long delay time from the input clock pulse.
I am not a Electronic Engineer, so probably any expert out there can correct me if I am thinking wrong.--------- As you can see below there is something common between JK and SR flipflop i.eThe JK flip-flop augments the behavior of the SR flip-flop by interpreting the S = R = 1 condition as a "flip" or toggle command. Specifically, the combination J = 1, K = 0 is a command to set the flip-flop; the combination J = 0, K = 1 is a command to reset the flip-flop; and the combination J = K = 1 is a command to toggle the flip-flop, i.e., change its output to the logical complement of its current value. Setting J = K = 0 does NOT result in a D flip-flop, but rather, will hold the current state. To synthesize a D flip-flop, simply set K equal to the complement of J. The JK flip-flop is therefore a universal flip-flop, because it can be configured to work as an SR flip-flop, a D flip-flop or a T flip-flop. NOTE: The flip flop is positive edge triggered (Clock Pulse) as seen in the timing diagram.even in the picture they Put SR/RS embeded, that mens JK can work like SR too. I will use this diagram to draw ripple counter. You may note similarity in input output combination too...RS table* We can summarize the operation of the RS-flipflop by the following truth table.R S Q Q' Comment 0 0 Q Q' Hold state 0 1 1 0 Set 1 0 0 1 Reset 1 1 ? ? AvoidJktableand the corresponding truth table is: J KQnext Comment 0 0 hold state 0 1 reset 1 0 set 1 1 toggleDoes that mean we use below coutner 'using 4 bit ripple counter using JK flip flops' as 4 bit ripple counter for RS flip flop too? at the max output states would differ only when both SR/JK is 1 1 ?Figure 1. A Simple Ripple Counter Consisting of J-K Flip-flopsMethod1: You will find answer here: http://www2.cs.uh.edu/~jhuang/JCH/LD/chap07.htmlHere you see how to create ripple counter using RS flip flop. Method 2: create a Toggle function in RS flip flop, then use it in place of typical jk flip flop ripple couters.
Sixteen. One bit per flip flop. A flip flop can represent only a true or a false. You need sixteen of these (1's and 0's) to make sixteen bits.
It can be seen that the external clock pulses (pulses to be counted) are fed directly to each J-K flip-flop in the counter chain and that both the J and K inputs are all tied together in toggle mode, but only in the first flip-flop, flip-flop A (LSB) are they connected HIGH, logic "1" allowing the flip-flop to toggle on every clock pulse. Then the synchronous counter follows a predetermined sequence of states in response to the common clock signal, advancing one state for each pulse. The J and K inputs of flip-flop B are connected to the output "Q" of flip-flop A, but the J and K inputs of flip-flops C and D are driven from AND gates which are also supplied with signals from the input and output of the previous stage. If we enable each J-K flip-flop to toggle based on whether or not all preceding flip-flop outputs (Q) are "HIGH" we can obtain the same counting sequence as with the asynchronous circuit but without the ripple effect, since each flip-flop in this circuit will be clocked at exactly the same time. As there is no propagation delay in synchronous counters because all the counter stages are triggered in parallel the maximum operating frequency of this type of counter is much higher than that of a similar asynchronous counter. Type your answer here...
flip -flop are nothing ,just latches, are used to store 1 bit values. suppose an 8 bit register can store 8 bits(1 byte) i.e. it comprizes of 8 latches/flip flop each bit corresponding to 1 flip flop
A flip-flop can act as a memory storage device because a flip-flop has one of two states, and it does not change state, so long as power is retained, until told to do so. One flip-flop corresponds to one bit of memory.
a 2 bit counter is a counter which have only 2 bits i.e. the posibble counting states are 00, 01, 10,11,00. It may also be known as MOD 3 counter. It can be realized by using 2 Flip flop.
library ieee; use ieee.std_logic_1164.all; entity 3bitrc is port(
Designing a 3 bit synchronous counter using jk flip flop is not an easy project for the uninformed. This is best left to professionals who are adept at programming. There are lengthy guides available on the internet if it is necessary to create one.
A D flip-flop for example.
One jk flip-flop with j=k=1 should be added to the system so that it's modulus becomes 16 instead of 8.
The flip-flop stores a bit and keeps that value until the opposite value is stored in it.