In order to answer this question, you need to know (a) its efficiency, and (b) its power factor at full load. 11 kW (not 'Kw') is its output power, so you need to know its efficiency in order to determine its input power. Then, because, for a three-phase system, power is equal to 1.732 times the product of the line voltage, line current, and power factor, you also need to know its power factor.
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
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Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
T430.247 of the NEC shows that a 1 hp motor operating at full load on 115v will draw 16 amps, called Full Load Current (FLC). Conductors supplying this motor are required to be 125% of FLC which is 20 amps. Motor circuits are complicated things and do not follow the rules of other circuits. This motor, while drawing a maximum of 16 amps at full load and supplied with #12 AWG copper conductors can be protected by a breaker of 40 amps.
A single phase 10 HP motor will draw aproximately 50 amps. A three phase 10 HP motor will draw aproximately 28 amps.
Yes, for a 15HP 3-phase 415V AC motor, each phase will draw approximately 26 Amps of current when running under normal operating conditions. This results in a total current draw of 26 Amps per phase for the motor.
For a 1hp 3-phase motor, the current draw will depend on the voltage supply. Typically, at 230V, a 1hp 3-phase motor will draw around 3.6 amps. However, this value may vary based on the motor efficiency and power factor.
read the name plate on the motor
For a 1.5 hp 230v 3 phase motor, you can calculate the amperage using the formula: Amps = (HP x 746) / (Volts x Efficiency x Power Factor x √3). Assuming an efficiency of 0.85 and a power factor of 0.8, the amperage draw would be approximately 4.3 Amps.
It depends on the voltage of the motor, and whether it is single-phase or 3-phase. A 120 VAC 2HP single phase motor draws almost 20 amps, a 240 VAC single-phase 2HP motor draws about 10 amps. A 480 VAC 2HP three-phase motor only draws about 6 amps.
The wiring should allow for 115 amps.
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
Assuming the power factor is 1, a 10 hp motor operating at 600 volts in a three-phase system would draw approximately 13.33 amps.
A single phase 5 HP motor operating at 220 volts will draw approximately 24 amps of current.
Then you are trying to get more HP out of the motor that it can supply. Back off on the load that the motor is driving or put a bigger motor onto the load.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%