Because many electronics, like power supplies, have internal energy storage in the form of capacitors. If you were to short the terminals, you would be shorting out the internal capacitors and thus creating a potentially hazardous situation. "Completing the circuit by internal resistance" allows the energy stored in the internal capacitors to bleed off slowly because the internal resistance is larger than a short.
(r+(c/2))
The internal resistance of a device is the resistance in ohms of that device. It is the resistance electrons need to overcome before electricity is said to flow.
internal resistance is always infinite in ideal current source .the internal resistance is in shunt with current source
no internal resistance of a cell cannot be considered to b as a defect because the resistance is so small as compared to the output we get from a cell this ristance can be neglected..
Because many electronics, like power supplies, have internal energy storage in the form of capacitors. If you were to short the terminals, you would be shorting out the internal capacitors and thus creating a potentially hazardous situation. "Completing the circuit by internal resistance" allows the energy stored in the internal capacitors to bleed off slowly because the internal resistance is larger than a short.
1. The capacitor has Lead resistance in series with the capacitor2. Since most capacitor use Dielectric and they have a leakage resistance and it is parallel to the Ideal Capacitor.
You can measure the emf of a cell by using a voltmeter, as this draws current from a cell. You can use the voltage, the emf, and the load resistance to determine the internal resistance of the cell.
it is a internal resistance of the devices like as capacitor and inductorCommentAs 'resistance' has a very specific meaning, I suggest that the above answer should read: 'It is the opposition of devices like capacitors and inductors (to the flow of current).'
Capacitors and Inductors theoretically consume no power. In real life, they only consume power because they have an internal resistance.
Internal resistance is approximately equal to 94.667
The voltage of the battery, and the resistance of the circuit (including the resistance of the wire and the internal resistance of the battery).
most capacitors will measure infinite resistancestarting capacitors are used to set up a rotating magnetic field by phase shifting a coil in a single phase motorwhen the motor gets up to speed a centrifugal switch will disconnect the capacitorthis happens at a random time and can leave the capacitor with a charge easily 4x the applied ac voltage (+/-1,000V)so some capacitors rated as starting capacitors will have an internal bleeding resistorGas discharge lamp ballast capacitors sometimes have discharge resistors.Microwave ovens have capacitors usually in a voltage doubling configuration(+/-20,000V) most have an internal bleeding resistor.Never rely on this resistor being intact or even present.It can have fatal consequences.the internal resistors are sized to discharge the capacitors in tens of minutesTc = R * C ( seconds = ohms * farads )
(r+(c/2))
It depends on the application. Voltmeters have a high internal resistance, while ammeters have a low internal resistance.
No, it is desirable for a battery to have a low internal resistance.
The internal resistance of a device is the resistance in ohms of that device. It is the resistance electrons need to overcome before electricity is said to flow.