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You'l need 5 4 to 1 muxes for making a 16 to 1 mux if your inputs are say W(0)-W(15) i.e 16 inputs ..... you start of with giving 4 inputs each to the 4 to 1 muxes the select lines for all 4 4 to 1 muxes will be common now each of the four 4 to 1 muxes is giving you one o/p so ..... take each of those 4 outputs and give them to the fifth 4 to 1 mux and voila you have a final o/p corresponding to 16 inputs !!! THIS IS HOW IT WILL LOOK LIKE inputs outputs mux 1 : w(0)w(1)w(2)w(3) m(1) mux2 : w(4)w(5)w(6)w(7) m(2) mux3 : w(8)w(9)w(10)w(11) m(3) mux4 : w(12)w(13)w(14)w(15) m(4) taking the above 4 outputs and giving them 2 mux5 mux5 : m(1)m(2)m(3)m(4) m(5) m(5) is the final output corresponding to 16 inputs W(0)-W(15)

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