The dc voltage of a rectified ac voltage will be the peak value of the ac voltage less the forward voltage drop of the diode.
The rms voltage of a sinusoidal ac voltage is sqrt(peak) / 2, but you also have to consider if the ac voltage is balanced around zero.
For a normal US house voltage of 117VAC, the peak voltage is about 165V, or 330V peak to peak. Your dc voltage is then around 164V.
Run that rectified voltage through a capacitor, and you will still have 164V peak value, but the voltage over time will dip because the capacitor will discharge during diode off time, and recharge when it turns back on.
AnswerA given value of a.c. rms voltage is exactly equivalent to the corresponding value of d.c. voltage. For example, 120 V (rms) is exactly equivalent to 120 V d.c. This is why the alternative name for 'rms voltage' is 'effective voltage'. This is based on the fact that a current of, say, 10 A (rms) will do exactly the same amount of work as a d.c. current of 10 A. And, of course, voltage and current are proportional.
You don't need to convert an rms value of voltage to find the DC equivalent -it is the DC equivalent! 120 V (rms) is exactly equivalent to 120 V DC.
Going back to basics, the rms value of an alternating current is equivalent to the value of a direct current. For example, 10 A (rms) will do precisely the same amount of work as 10 A DC. Since voltage and current are proportional (Ohm's Law), then the same applies to a voltage.
Ac x 1.4 -1.4=dc
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.
Yes, if you provide a rectifier to convert the AC into DC. This is how early AC voltmeters worked. They rectified the AC into DC, and the DC voltmeter measured something related to the peak voltage. In order to calibrate, you then considered that RMS voltage is peak voltage divided by the square root of 2. The problem with that approach is that it only works for sinusoidal AC. If the AC is some other shape, such as square or triangular, then the calibration does not work correctly. Modern AC voltmeters measure true RMS using signal processing techniques. If you attempt to measure AC with a DC voltmeter without a rectifier, it may or may not work, depending on the design of the meter. An ordinary VOM style meter would read zero, because the average voltage of an AC waveform is zero.
"Voltage peak" is generally used to denote the maximum(amplitude) of AC voltage supply. It can not be approximated as dc value. The closest approximation one can make for dc value of a ac supply is the RMS(root mean square) value of the voltage. So that the ohmic loss caused by the given AC voltage supply is equivalent to that caused by a dc supply having value equal to the RMS of this AC supply (for given impedance & time).
yes it is possible.we can convert dc into ac using inverter.this inverter is diff than our home inverter or using commutator.
How do you convert 23 voltage DC to 230 Voltage AC?
no, dc volatage is a type of current direct current, ac is alternating current, average voltage could be any type of voltage ac or dc that maintains a constant rangeAnswerNo. A DC voltage is exactly equivalent to an AC rms-voltage. So, for example, 100 V (DC) is exactly equivalent to 100 V (AC rms). The average value of an AC waveform is zero.
With an AC and a DC voltage source in series, the DC voltage can be added to the RMS value of the AC voltage to give the effective voltage.
Ac x 1.4 -1.4=dc
To convert AC voltage to DC voltage.
To convert DC values to AC values if you are wanting RMS values they are the same. 100V DC and 100V AC (RMS) are the same "value". If you want to know the Peak-To-Peak AC value you would multiply the RMS value by 1.414. So 100V AC RMS equals 141.4 V Peak to Peak.
RMS voltage is the DC equivalent of your AC waveform. Vrms=(Vpeak)/(root two) If your peak voltage is 170V then the RMS voltage would be approx. 120 V (see related link)
You rectify AC voltage through a diode bridge to convert it to DC.
Peak voltage will be 1.414 times the RMS. Peak to Peak voltage, assuming no DC offset, will be 2 x 1.414 x the RMS value.
You can make it so it does either increase or decrease. The limiting factor is that power out cannot exceed power in. So going to a higher voltage will limit current and going to a lower voltage will increase current available. A2 Because AC is continuously changing in a sinusoidal waveform, it is hard to determine the exact voltage. It is usually called by it's RMS value (Root Mean Squared). The result is that when you fully rectify an AC voltage, the DC voltage is actually HIGHER than the RMS AC voltage.
Yes, if you provide a rectifier to convert the AC into DC. This is how early AC voltmeters worked. They rectified the AC into DC, and the DC voltmeter measured something related to the peak voltage. In order to calibrate, you then considered that RMS voltage is peak voltage divided by the square root of 2. The problem with that approach is that it only works for sinusoidal AC. If the AC is some other shape, such as square or triangular, then the calibration does not work correctly. Modern AC voltmeters measure true RMS using signal processing techniques. If you attempt to measure AC with a DC voltmeter without a rectifier, it may or may not work, depending on the design of the meter. An ordinary VOM style meter would read zero, because the average voltage of an AC waveform is zero.
first it converts ac to dc as rectifier But the required dc voltage is obtained by taking average of on & off DC input voltage.