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Lets work the mathematics:

  • Power equation, P = VI
  • Ohm's law, R = V/I

Combine these equations to solve for current:

  • P/I = V
  • R = P/I2
  • I2 = P/R
  • I = (P/R)-2

Substituting and solving:

  • I = (0.5 / 2200)-2 = 15mA
  • I = 15mA
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Q: A 2.2 kohm resistor that dissipates 0.5 W what is the current?
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