sodium must lose one electron
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For sodium to become stable, it must lose one electron to achieve a full outer electron shell. This typically occurs through the formation of an ionic bond with another atom that can accept this extra electron, such as chlorine. Once sodium loses its electron and forms a stable bond, it becomes a stable compound.
Sodium is a highly reactive metal and is not considered durable in its pure form. It readily reacts with water and air, leading to its degradation. Special precautions must be taken to handle and store sodium due to its reactivity.
Oxygen must bond twice to become stable. In its stable form, oxygen molecules have a double bond (O=O), with each oxygen atom sharing two electrons.
It keeps its neutrons but loses one electron. Protons and neutrons do not move in a chemical reaction. Sodium, being in group one, must lose one electron to have a complete outer electron shell and thus be stable.
Sodium must lose one electron to achieve a stable octet configuration since it has 11 protons and would complete its outer shell to achieve the stable electron configuration of the nearest noble gas, neon, with 10 electrons.
For fluorine to become stable, it needs to gain one electron to attain a full valence shell, similar to the electron configuration of neon. Fluorine has seven valence electrons in its outer shell, so gaining one electron would fill its outer shell and make it stable with a full octet like neon.