What is this equation correctly balanced Cu2S O2 Cu2O SO2?

Answer 1

The balanced equation for the reaction between copper(II) sulfide (Cu2S) and oxygen (O2) to form copper(I) oxide (Cu2O) and sulfur dioxide (SO2) is as follows:

2Cu2S + 3O2 -> 2Cu2O + 2SO2

This balanced equation ensures that the number of atoms of each element is the same on both sides of the reaction, satisfying the law of conservation of mass. The coefficients in front of each compound indicate the relative amounts of each substance involved in the reaction.

Answer 2

Cu2S + O2 ---> Cu2O + SO2

On the left hand side we count up all the individual atoms:

Cu = 2

S = 1

O = 2

On the right hand side we do the same:

Cu = 2

S = 1

O = 3

Notice we have one extra O atom on the right? To fix that we would have to have 11/2 O2 on the left hand side.

Cu2S + 11/2O2 ---> Cu2O + SO2

Because you can't use fractions when balancing equations, we double the whole equation, resulting in a balanced equation with no fractions.

2Cu2S + 3O2 ---> 2Cu2O + 2SO2

Answer 3

The balanced equation is: 2Cu2S + 3O2 -> 2Cu2O + 4SO2

Answer 4

First, the category you chose for this question is way off...but ill answer it. i believe its Cu2O plus C yields Cu2 plus CO.

Answer 5

2Cu + O2 -> 2Cu2O

Answer 6

2Cu2S + 3O2 --> 2Cu2O + 2SO2