2KI + F2 ----> 2KF + I2
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When fluorine reacts with potassium iodide, potassium fluoride and iodine are produced. The balanced chemical equation for this reaction is: 2KI + F2 -> 2KF + I2.
The word equation for the reaction between bromine and potassium iodide is: bromine + potassium iodide -> potassium bromide + iodine.
The balanced symbol equation between fluorine and potassium iodide is: 2KI + F2 --> 2KF + I2
When fluorine reacts with potassium bromide, the fluorine displaces bromine from the compound to form potassium fluoride and bromine gas. This is a redox reaction where fluorine is reduced and bromine is oxidized.
When bleach is mixed with potassium iodide, it undergoes a redox reaction. The bleach oxidizes the iodide ions to produce iodine, which can be observed as a brown color. This reaction can be used to test for the presence of bleach in a solution.
A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.