What is the reaction between lead acetate solution and potassium iodide solutions?

Answer 1

Lead(II) nitrate reacts with potassium iodide in solution to produce the spectator species potassium nitrate, and a bright-yellow lead(II) iodide precipitate. This is a common reaction in high school chemistry. The balanced equation is: Pb(NO3)2(aq) + 2KI(aq) --> 2KNO3(aq) + PbI2(s)

Answer 2

The reaction between lead acetate solution and potassium iodide solution results in the formation of lead iodide precipitate and potassium acetate solution. This reaction is a double displacement reaction where the ions of the two compounds switch partners to form the new products. The lead iodide precipitate is insoluble in water and appears as a yellow solid.

Answer 3

When lead acetate reacts with potassium iodide then lead iodide PbI2 which is an yellow precipitate is formed. This is a double displacement reaction.The balanced chemical equation for this:-

Pb(CH3COO)2 + 2 KI = PbI2 + 2 K(CH3COO)

Answer 4

Pb(CH3COO)2 + KI ---> (?) aq + aq ---> s + aq




The Solution is a yellow powder in water (you can see it clearly if you filter it).

Answer 5

yes

when added together the solution will turn yellow and after a while leave powdery sediment at the bottom

Answer 6

if the potassium iodide mix with lead II nitrate it will results a brigth yellow color. it means that the two substance are reactive tats why is it results that color.

Answer 7

Yes it does. Because the Fluorine is more reactive than iodine it will form potassium fluoride and iodine.

2KI + F2 --> 2KF + I2

Answer 8

If solutions are mixed, then lead iodide will precipitate.

Pb2+ + 2I- --> PbI2(s)

Answer 9

yes. the combined chemicals create a yellowish slime, a little like oobleck, if you've ever done that experiment. its toxic though, so don't play with it!

Answer 10

Pb(CH3COO)2 + 2 KI = PbI2 + 2 K(CH3COO)

PbI2 is an yellow precipitate.