To find the mass of carbon as a percent of the molecule, you have to first know the mass of the whole molecule. This can be done with the atomic weights of the elements and multiplying them by the number of atoms in a single molecule of hexachlorophene (the given compound).
Carbon: 12.0 g/mol × 13 = 156
Hydrogen: 1.0 g/mol × 6 = 6.0
Chlorine: 35.5 g/mol × 6 = 213
Oxygen: 16.0 g/mol × 2 = 32.0
C13H6Cl6O2 = 407 g/mol
(Mass of carbon ÷ total mass) × 100 = % carbon by mass
(156 ÷ 407) × 100 = 38.3% carbon
To calculate the percent of carbon by mass in C4H10O, first determine the molar mass of the compound: C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol. The total molar mass of C4H10O is 74.12 g/mol. Then, calculate the mass contribution of carbon: 4(12.01 g/mol) / 74.12 g/mol = 0.648. Finally, convert this to a percentage by multiplying by 100% to get 64.8% carbon by mass.
First find the molar mass of C10H14N2 by multiplying the number of atoms of each element times its molar mass (atomic weight on the Periodic Table). Then add the molar masses of each element. The sum is the molar mass of the compound.
C: 10 x 12.011g/mol = 120.11g/mol
H: 14 x 1.008g/mol = 14.11g/mol
N: 2 x 14.007g/mol = 28.014g/mol
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Total = 162.23g/mol = molar mass of C10H14N2
Percent carbon by mass = mass of C/mass of C10H14N2 x 100 = (120.11g/mol)/(162.23g/mol) x 100 = 74.037% C by mass
The molar mass of carbon dioxide (CO2) is 44 g/mol. Carbon has a molar mass of 12 g/mol and oxygen has a molar mass of 16 g/mol. So, in 44g of CO2, there are 12g of carbon. Therefore, the percent by mass of carbon in 44g of carbon dioxide is (12g / 44g) x 100 = 27.3%.
To calculate the percent by mass of carbon in carbon dioxide, first determine the molar mass of CO2 (12 g/mol for carbon and 32 g/mol for oxygen). Then divide the molar mass of carbon by the molar mass of CO2 and multiply by 100 to get the percentage. In this case, the percent by mass of carbon in 44 g of CO2 is (12 g/mol / 44 g/mol) * 100 = 27.27%.
To calculate the percent by mass of carbon in C3H8, you first need to determine the molar mass of the entire compound. C3H8 has a molar mass of 44 g/mol. The molar mass of carbon in C3H8 is 3 * 12 g/mol = 36 g/mol. To find the percent by mass of carbon, divide the molar mass of carbon by the molar mass of the compound and multiply by 100: (36 g/mol / 44 g/mol) * 100 ≈ 81.8%.
Acetone's percent composition by mass is 62.13% carbon, 31.82% oxygen, and 6.05% hydrogen.
Carbonic acid - H2CO3 Find the atomic masses of each element and multiply it by however many atoms are in the compound, then add them together. H = 1.007 × 2 = 2.014 C = 12.01 O = 16.00 × 3= 48.00 Molecular mass = 2.014 + 12.01 + 48.00 = 62.02 grams/mole Take the mass of a specific element (above) and divide it by the total molecular mass. Change the final answer to a percent Hydrogen: 2.014 ÷ 62.02 = .0325 = 3.25% Carbon: 12.01 ÷ 62.02 = .194 = 19.4% Oxygen: 48.00 ÷ 62.02 = .774 = 77.4% Carbonic acid contains 3.25% Hydrogen, 19.4% Carbon, and 77.4% Oxygen.
The compound name for C4H10O is butanol. It is an alcohol with a four-carbon chain and a hydroxyl functional group.
The molar mass of carbon monoxide (CO) is 28.01 g/mol. The molar mass of carbon is 12.01 g/mol. To find the mass percent of carbon in CO, you divide the molar mass of carbon by the molar mass of CO and multiply by 100. (12.01 g/mol / 28.01 g/mol) x 100 = 42.9% Therefore, the mass percent of carbon in carbon monoxide is approximately 42.9%.
To find the percent by mass of carbon in acetone (C3H6O), calculate the molar mass of carbon in acetone by adding the molar masses of the individual atoms: (3 × atomic mass of carbon) / molar mass of acetone × 100. This will give you the percentage of carbon in acetone by mass.
To determine the percent composition of carbon in beryllium cyanide, first find the molar mass of beryllium cyanide, then calculate the molar mass contributed by carbon. Finally, divide the molar mass of carbon by the total molar mass of beryllium cyanide and multiply by 100 to get the percent composition.
The formula for butane-1-ol is C4H10O. It is an alcohol compound that consists of four carbon atoms, ten hydrogen atoms, and one oxygen atom.
Carbon has a atomic mass of 12.So its percentage is 75%
The molar mass of carbon dioxide (CO2) is 44 g/mol. Carbon has a molar mass of 12 g/mol and oxygen has a molar mass of 16 g/mol. So, in 44g of CO2, there are 12g of carbon. Therefore, the percent by mass of carbon in 44g of carbon dioxide is (12g / 44g) x 100 = 27.3%.
Dimethylsulfoxide (DMSO) has a molar mass of 78.13 g/mol and a molecular formula of (CH3)2SO. The molar mass of carbon is 12.01 g/mol. To calculate the mass percent of carbon in DMSO, first calculate the molar mass contribution of carbon (12.01 g/mol * 2) and divide it by the molar mass of DMSO (78.13 g/mol) to get the mass percent. This gives a mass percent of carbon in DMSO of about 30.8%.
The molar mass of methyl ethyl ether (C4H10O) is approximately 74.12 g/mol.
Oxygen, carbon, hydrogen, and nitrogen make up over 90 percent of the mass of the human body.
Carbon tetrachloride is composed of one carbon atom and four chlorine atoms. To calculate the percent of chlorine in carbon tetrachloride, you would divide the molar mass of chlorine by the molar mass of the compound and multiply by 100. In this case, the percent of chlorine in carbon tetrachloride is approximately 82.3%.
Carbon disulfide (CS2) is composed of one carbon atom and two sulfur atoms. To calculate the percent composition, divide the mass of each element by the molar mass of CS2, then multiply by 100 to get the percentage. The percent composition of CS2 is approximately 45.7% carbon and 54.3% sulfur.