It is 1 x 10-14
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At 101.3 kPa and 298 K, the element present is likely to be oxygen (O2) due to its high natural abundance in the atmosphere and its physical properties at that temperature and pressure.
Carbon dioxide (CO2) is formed from its elements (carbon and oxygen) by an exothermic reaction at 298 K and 101.3 kPa.
To convert Fahrenheit to Kelvin, you can use the formula K = (F - 32) x 5/9 + 273.15. Plugging in 298 degrees Fahrenheit gives you K = (298 - 32) x 5/9 + 273.15, which equals approximately 425.37 Kelvin.
To convert Celsius to Kelvin, add 273. So, the Kelvin temperature of 25 degrees Celsius is 298 Kelvin (25 + 273 = 298).
To solve this problem, we can use the combined gas law formula: P1V1/T1 = P2V2/T2 By substituting the values: (98.7 kPa)(10 L)/(298 K) = (102.7 kPa)(V2)/(293 K) Rearranging the equation gives: V2 = (98.7 kPa * 10 L * 293 K) / (102.7 kPa * 298 K) ≈ 9.75 L Therefore, the volume at 20°C and 102.7 kPa would be approximately 9.75 liters.
Water boils at the highest numerical value on the Kelvin scale, at 373.15 K.
Oxygen is a gas at 298 K.
Yes, there is a pOH value in acidic solutions which is above 7.0 at the temperature of 298 K.
298 degrees Fahrenheit = 420.93 K.
At the temperature of 298 K, any pH value lesser than 7.0 is considered to be acidic.
It is: x = k whereas k is a numerical value on the x axis and is a line parallel to the y axis through (k, 0)
That ' K ' means ' 1,000 '. Divide 'watts' by 1,000 to get 'Kw' .
To answer that, you'll need to have a numerical value for the letters.
It means thousand. So if someone said their salary is 200k then they mean 200 thousand.
In mathematics, "k" is a variable that can represent any number or value depending on the context in which it is used. It is a placeholder for an unknown quantity that can be determined through algebraic manipulation or given numerical values in equations or formulas. The specific value of "k" would need to be provided or solved for in order to determine its exact value in a given mathematical problem.
The average velocity of hydrogen molecules at 298 K can be calculated using the root mean square velocity formula, v = √(3kT/m), where k is the Boltzmann constant, T is the temperature in Kelvin, and m is the mass of a hydrogen molecule. The average velocity of hydrogen at 298 K would be around 1926 m/s.
At 101.3 kPa and 298 K, the element present is likely to be oxygen (O2) due to its high natural abundance in the atmosphere and its physical properties at that temperature and pressure.