To determine the number of sulfur atoms present in 9.96 grams of sulfur trioxide (SO3), you need to first calculate the number of moles of sulfur trioxide using its molar mass. Then, since one molecule of sulfur trioxide contains 1 sulfur atom, you can directly convert the moles of SO3 to moles of sulfur atoms. Finally, use Avogadro's number (6.022 x 10^23) to convert moles of sulfur atoms to the number of sulfur atoms.
In sulfur trioxide (SO3), there are 1 sulfur atom and 3 oxygen atoms. Therefore, in 2.00 moles of SO3, there would be 2.00 moles of sulfur atoms and 6.00 moles of oxygen atoms.
To calculate the mass of 6.11 moles of sulfur trioxide (SO3), you would multiply the number of moles by the molar mass of SO3. The molar mass of SO3 is approximately 80.06 g/mol. Therefore, the mass of 6.11 moles of SO3 would be around 489.67 grams.
The stoichiometry of the reaction between sulfur dioxide and oxygen to produce sulfur trioxide is 2SO2 + O2 -> 2SO3. This means that 2 moles of SO3 are formed from 2 moles of SO2. Therefore, if 3 moles of SO2 are used, 3/2 = 1.5 moles of SO3 will be formed.
The compound with the formula SO3 is called sulfur trioxide.
One mole of sulfur reacts with 1.5 moles of oxygen to produce one mole of sulfur trioxide. So, with two moles of sulfur and three moles of oxygen, the limiting reactant is sulfur. Therefore, two moles of sulfur will produce two moles of sulfur trioxide.
To determine the number of sulfur atoms present in 9.96 grams of sulfur trioxide (SO3), you need to first calculate the number of moles of sulfur trioxide using its molar mass. Then, since one molecule of sulfur trioxide contains 1 sulfur atom, you can directly convert the moles of SO3 to moles of sulfur atoms. Finally, use Avogadro's number (6.022 x 10^23) to convert moles of sulfur atoms to the number of sulfur atoms.
In sulfur trioxide (SO3), there are 1 sulfur atom and 3 oxygen atoms. Therefore, in 2.00 moles of SO3, there would be 2.00 moles of sulfur atoms and 6.00 moles of oxygen atoms.
To calculate the mass of 6.11 moles of sulfur trioxide (SO3), you would multiply the number of moles by the molar mass of SO3. The molar mass of SO3 is approximately 80.06 g/mol. Therefore, the mass of 6.11 moles of SO3 would be around 489.67 grams.
There are two elements present in sulfur trioxide, which are: Sulfur and Oxygen.The following formula represents sulfur trioxide: SO3As there is one atom of sulfur and three atoms of oxygen (trioxide).
The limiting reactant is oxygen.
The stoichiometry of the reaction between sulfur dioxide and oxygen to produce sulfur trioxide is 2SO2 + O2 -> 2SO3. This means that 2 moles of SO3 are formed from 2 moles of SO2. Therefore, if 3 moles of SO2 are used, 3/2 = 1.5 moles of SO3 will be formed.
The compound with the formula SO3 is called sulfur trioxide.
Sulfur tetraoxide 2- SO4 is sulfate
Sulfur trioxide is a byproduct of sulfuric acid. In large quantities, sulfur trioxide can be deadly. For the most part, small quantities of sulfur trioxide will not hurt you.
Sulfur trioxide has a trigonal planar molecule.
The compound for sulfur trioxide is SO3.