6.941
To work this out, the stoichiometry formula n=m/M will be used. as the Atomic Mass of lithium is 6.941, the equation would be stated as, n=6/6.941.
this equals 0.864429Mol. however this would be written as 0.9 mol due to significant figures.
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
The molar mass of lithium is approximately 6.94 g/mol. Therefore, for 5.40 moles of lithium, the mass would be calculated as: 5.40 moles x 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
To find the number of moles of Li atoms in 10.56g of Li, you need to divide the given mass by the molar mass of Li (6.94 g/mol). 10.56g / 6.94 g/mol = 1.52 moles of Li atoms.
The gram Atomic Mass of lithium is 6.941; this is the amount of lithium that contains Avogadro's Number of atoms. Therefore, in 18.7 g of lithium, there will be (18.7)/(6.941) times Avogadro's Number of atoms, or about 1.62 X 1024, to the justified number of significant digits.
To find the number of moles in 51 grams of lithium phosphate, you first need to determine its molar mass. The molar mass of lithium phosphate (Li3PO4) is 115.79 g/mol. To find the number of moles, divide the given mass by the molar mass: 51 g / 115.79 g/mol β 0.44 moles of lithium phosphate.
To find the number of moles of lithium in 27.6 g, you first need to determine the molar mass of lithium, which is approximately 6.94 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 27.6 g Γ· 6.94 g/mol β 3.98 moles of lithium.
To find the number of moles in 1.9 g of lithium, you need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. So, 1.9 g / 6.94 g/mol β 0.274 moles of lithium.
The molar mass of lithium is approximately 6.94 g/mol. To find the mass of 5.40 moles of lithium, multiply the number of moles by the molar mass: 5.40 moles * 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
3.977 mol
To convert moles to grams, you need to know the molar mass of lithium, which is approximately 6.94 g/mol. Multiplying the number of moles (0.0864 mol) by the molar mass (6.94 g/mol) gives you approximately 0.6 grams of lithium.
To find the number of atoms in 11.8 g of lithium, you need to first calculate the number of moles of lithium present using the atomic mass of lithium (6.941 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To convert grams of lithium to moles, we need to divide the mass of lithium by its molar mass. The molar mass of lithium is approximately 6.94 g/mol. Moles = 318.0 g / 6.94 g/mol = 45.82 moles. Therefore, 318.0 grams of lithium is equivalent to 45.82 moles.
The molar mass of lithium is 6.94 g/mol. Thus, for 3 moles of lithium, the mass would be: 3 moles x 6.94 g/mol = 20.82 grams of lithium.
0.0000639mol
The molar mass of lithium is approximately 6.94 g/mol. Therefore, for 5.40 moles of lithium, the mass would be calculated as: 5.40 moles x 6.94 g/mol = 37.476 g. So, the mass of 5.40 moles of lithium is 37.476 grams.
To convert moles of lithium to grams, you need to multiply the number of moles by the molar mass of lithium. The molar mass of lithium is 6.94 g/mol. Therefore, 0.0295 mol of lithium is equal to 0.0295 mol * 6.94 g/mol = 0.2053 grams.
To find the number of moles of Li atoms in 10.56g of Li, you need to divide the given mass by the molar mass of Li (6.94 g/mol). 10.56g / 6.94 g/mol = 1.52 moles of Li atoms.