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EzraThe molar mass of lithium oxide (Li2O) is calculated by adding the molar masses of lithium (Li) and oxygen (O).
Molar mass of Li = 6.94 g/mol Molar mass of O = 16.00 g/mol
Molar mass of Li2O = 2*(molar mass of Li) + molar mass of O = 2*(6.94) + 16.00 = 14.88 + 16.00 = 30.88 g/mol
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What compounds has the highest molar mass sodium iodide sodium bromide sodium chloride lithium bromide lithium fluoride?
Sodium iodide has the highest molar mass among the compounds listed, with a molar mass of 149.89 g/mol. Sodium bromide has a molar mass of 102.89 g/mol, sodium chloride has a molar mass of 58.44 g/mol, lithium bromide has a molar mass of 86.85 g/mol, and lithium fluoride has a molar mass of 25.94 g/mol.
What is the molarity of 1.5 liters of an aqueous solution that contains 52 grams of lithium flouride?
The molarity of the solution can be calculated by first finding the moles of lithium fluoride using its molar mass, which is 25.94 g/mol for lithium and 19.00 g/mol for fluorine. Add these together to find the molar mass of lithium fluoride. Then, divide the mass of lithium fluoride by its molar mass to get the moles. Finally, divide the moles by the volume of the solution in liters to get the molarity.
How do you find the molar mass of beryllium oxide?
To find the molar mass of beryllium oxide (BeO), you will need to determine the individual molar masses of beryllium (Be) and oxygen (O) from the periodic table and then add them together. The molar mass of Be is about 9 g/mol and the molar mass of O is about 16 g/mol. When you add them together, you'll find that the molar mass of BeO is approximately 25 g/mol.
What is the mass of 24.6 formula units of magnesium oxide?
To find the mass of 24.6 formula units of magnesium oxide, we first need to determine the molar mass of magnesium oxide. Magnesium has a molar mass of approximately 24.3 g/mol, and oxygen has a molar mass of approximately 16.0 g/mol. Therefore, the molar mass of magnesium oxide (MgO) is 24.3 + 16.0 = 40.3 g/mol. Next, we multiply the molar mass of MgO by the number of formula units (24.6) to find the total mass: 40.3 g/mol x 24.6 = 992.38 grams. Therefore, the mass of 24.6 formula units of magnesium oxide is approximately 992.38 grams.
What mass of sodium is needed to produce 108.2 g of sodium oxide?
To calculate the mass of sodium needed to produce 108.2 g of sodium oxide, you need to determine the molar mass ratio between sodium and sodium oxide. Sodium oxide has a molar mass of 61.98 g/mol, while sodium has a molar mass of 22.99 g/mol. Using stoichiometry, you can calculate that you need (2 * 22.99) g of sodium to produce 108.2 g of sodium oxide.
