Cobalt = Co transition metal and has a charge of 3+
Bromide = Br halogen and has a charge of 1-
Co of 3+ and Br of 1-
Cross method
Metal First
Formula: CoBr3
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Co+2 Br-1 <--- these are the ions and their charges
Co+2 Br-1 Br-1 <--- the charges have to add up to zero, so one+2 cobalt ion cancels out two -1 bromine ions
CoBr2 <--- simplify
CoBr6 Cobalt is +6 (that's what the Roman numeral VI tells you) and bromine has a charge of -1, so you need 6 of them. I don't know that Co(VI) bromide exists - Co tends to form +2 and +3 complexes, not +6.
Co2S3 is the chemical formula for cobalt(III) sulfide, which is a compound consisting of cobalt and sulfur. It is a black solid that is used as a catalyst in certain chemical reactions.
The formula for copper(I) bisulfate is CuHSO4.
The chemical formula for ammonium bisulfate is NH4HSO4.
The chemical formula for ammonium bisulfate is (NH4)HSO4.
The formula for cobalt(III) iodide is CoI3. It is composed of one cobalt ion with a +3 charge and three iodide ions with a -1 charge each, resulting in a neutral compound.