The answer to this question must be in Perry's Chemical Engineering Handbook, or the CRC Handbook of Chemistry and Physics, or the JANAF Thermochemical Tables... I just don't have mine handy right now, and I need the same answer for a homework problem. These books have the enthalpy of formation for a myriad of substances. Go to your nearest library and look it up!
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Mixing copper sulfate and sodium carbonate would be considered a chemical reaction because a new substance is formed as a result of the reaction between the two compounds, resulting in the formation of copper carbonate and sodium sulfate.
Na2SO4 is sodium sulfate sometimes called disodium sulfate. Sodium sulfate from a natural source is known as thenardate and was formerly called Glauber's Salt.
There are 2.42 grams of sodium in 10 grams of sodium sulfate (Na2SO4). This is calculated based on the molecular weight of sodium sulfate and the molar ratio of sodium to the sulfate ion in the compound.
The valency of sodium in sodium sulfate is +1, while the valency of sulfate is -2. Therefore, the valency of sodium sulfate as a whole is +2.
The formula for sodium sulfate is Na2SO4, representing a compound composed of two sodium ions (Na+) and one sulfate ion (SO4^2-).
The standard enthalpy of formation for sodium sulfate is -1385.2 kJ/mol.
Combining sodium sulfate and barium nitrate would result in the formation of barium sulfate and sodium nitrate. Barium sulfate is a white precipitate that is insoluble in water, while sodium nitrate remains in solution.
The reaction between sodium hydroxide and copper sulfate will result in the formation of sodium sulfate and copper hydroxide. The products of this reaction will be a blue precipitate of copper hydroxide and a solution of sodium sulfate.
One common method to test for sodium sulfate is by performing a precipitation reaction. Mixing a solution of sodium sulfate with a solution of barium chloride will result in the formation of a white precipitate of barium sulfate. The presence of this precipitate confirms the presence of sulfate ions, indicating the presence of sodium sulfate in the original solution.
The standard enthalpy change of formation of sodium (ΞHfΒ°) is 0 kJ/mol. This means that the enthalpy change when 1 mole of sodium is formed from its elements in their standard state is zero.
The enthalpy of formation is the change in enthalpy that occurs when 1 mole of a compound is formed from its elements in their standard states. The enthalpy of combustion is the change in enthalpy that occurs when 1 mole of a substance is completely burned in oxygen. In short, enthalpy of formation is for the formation of a compound, while enthalpy of combustion is for the complete burning of a substance.
Oxygen gas (O2) does not have an enthalpy of formation because it is an element in its standard state, which has an enthalpy of formation of zero by definition. Ozone (O3), on the other hand, is a compound and has a defined enthalpy of formation because it is formed from its elements in their standard states.
Barium nitrate and sodium sulfate react to form barium sulfate and sodium nitrate in a double displacement reaction. This reaction results in the formation of a white precipitate of barium sulfate, which is insoluble in water.
When sodium hydrogen sulfate is added to sodium carbonate, a double displacement reaction occurs. This results in the formation of sodium sulfate and carbonic acid. However, carbonic acid is unstable and breaks down into water and carbon dioxide.
A negative enthalpy of formation indicates that energy is evolved.
The ionisation enthalpy of potassium is lower than that of sodium.
Calcium sulfate (CaSO4) forms a saturated solution first compared to sodium chloride (NaCl) because calcium sulfate has lower solubility in water than sodium chloride. This means that calcium sulfate will reach its maximum solubility point in water sooner than sodium chloride, resulting in the formation of a saturated solution.