The blue color in copper sulfate solution is due to the presence of the copper (II) ion (Cu2+). This ion absorbs certain wavelengths of light, resulting in the blue color that we see.
CuCl2(aq) + K2S(aq) --> CuS(s) + 2KCl(aq) K and Cl are spectators so the net ionic would be: Cu2+(aq) + S2-(aq) --> CuS(s)
In the reaction Zn + CuCl2 → ZnCl2 + Cu, CuCl2 is the oxidizing agent because it accepts electrons from Zn, causing zinc to be oxidized and copper to be reduced.CuCl2 itself gets reduced to Cu.
It is Copper chloride.It is written as Copper(ii) chloride.
When copper nitrate reacts with barium chloride, a white precipitate of barium nitrate is formed. Copper chloride remains in solution as ions. This reaction can be represented by the equation: Cu(NO3)2 + BaCl2 -> Ba(NO3)2 + CuCl2.
Yes, CuCl2 (copper (II) chloride) is soluble in water and forms an aqueous solution.
The flame color of CuCl2 is blue-green. This color is often observed when copper compounds are heated in a flame.
When NaSO3 is added to CuCl2 solution, a white precipitate of CuSO3 forms. Copper(II) sulfite is insoluble in water, causing it to precipitate out of the solution.
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
CuCl2 does NOT burn per se. However, when CuCl2 is dissovled in water in to Cu^2+ ions and Cl^- ions. Pass a ni-chrome or platinum wire through the solution, and then pass the wire through a Bunsen Burner flame. The flame colour will becomes a beautiful Blue/Green colour.
Copper(II) chloride (CuCl2) is not a base; it is a salt that is composed of copper(II) cations and chloride anions. It is an ionic compound that can dissociate in solution to form copper ions and chloride ions.
First, calculate the moles of CuCl2 in 5.8g. Then, use the molarity of CuCl2 to find the initial moles of CuCl2 in 131ml of the original solution. Finally, calculate the volume of the diluted solution needed for 50.5ml to contain the moles of CuCl2 obtained.
When copper(II) carbonate (CuCO3) reacts with hydrochloric acid (HCl), copper(II) chloride (CuCl2) and carbon dioxide gas (CO2) are produced. The green color observed is due to the formation of copper(II) chloride, which has a greenish color.
The equation is: Zn(s) + CuCl2(aq) --> ZnCl2(aq) + Cu(s)
Copper is corroded in a sodium chloride solution; CuCl2 is formed.
As gaseous ammonia with solid coppersulfate: 2NH3(g) + CuSO4(s) --> Cu(NH3)2SO4(s) With water: [Cu(NH3)2]2+ complex-ions with SO42- ions in aquous solution (deep blue color)
CuCl2(s) = Cu^2_(aq) + + 2Cl^-(aq) In solution the chloride anions )Cl^-) are colourless ; see also dissolved common salt (NaCl) So it must be the copper cations (Cu^2+) that gives the colour blue.