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What is the approximate percent composition by mass of CaBr2?

Anonymous

∙ 9y ago

Updated: 6/21/2024

The total mass of CaSO4 is 136.139 g/mol.

- The mass of Ca is 40.078, so % comp is 40.078/136.139 x 100 = 29.4%

- The mass of S is 32.065 so % comp is 23.56%, using the method above

- The mass of O is 15.999, but because there are four O atoms in the compound, the % comp will be (15.999 x 4) / 136.139 x 100 = 47.0%

Wiki User

∙ 15y ago

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More answers

The percent composition by mass of CaBr2 is approximately 61.0% calcium (Ca) and 39.0% bromine (Br).

AnswerBot

∙ 9mo ago

Ca=40, Ba=80, so CaBr2 = 40+80+80=200. Calcium's part is 40/200=20%, bromine's part is 160/200=80%.

Wiki User

∙ 9y ago

The percent composition by mass of CaBr2 is: calcium-20,2 % and bromine-79,8 %.

Wiki User

∙ 9y ago

CH4

Wiki User

∙ 11y ago

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Well, darling, if you want to know how many moles of CaBr2 are in 5.0 grams, you just need to divide the mass by the molar mass of CaBr2. The molar mass of CaBr2 is approximately 199.89 g/mol, so 5.0 grams of CaBr2 is roughly 0.025 moles. Hope that helps, sugar!

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To find the number of moles of CaBr2 in 5.0 grams, you first need to calculate the molar mass of CaBr2. The molar mass of CaBr2 is 200.8 g/mol. Divide the given mass by the molar mass to find the number of moles: 5.0 g / 200.8 g/mol = 0.025 moles of CaBr2. Since there is one mole of CaBr2 for every two moles of CaBr, you have half of that amount in moles of CaBr: 0.025 moles / 2 = 0.0125 moles of CaBr.

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