H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)
Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
OH- + H+ H2O
Balanced Molecular Equation:HCl(aq) + NaOH(aq) --> NaCl(aq) + H2O(l)Complete Ionic Equation:H+ (aq) + Cl- (aq) + Na+ (aq) + OH- (aq) -->Na+ (aq) + Cl- (aq) + H2O (l)Cancel out the "spectator" ions, or ions that do not change in structure or charge (on both sides of the equation; "cancel out")Net Ionic Equation:H+ (aq) + OH- (aq) --> H2O(l)User forgot to place the yield arrows (separating products from reactants)
The net ionic equation for sodium acetate (NaCH3COO) and potassium nitrate (KNO3) is: CH3COO^- + K^+ -> KCH3COO
(2 Na+ + HS- + OH-)(aq) + 2 (Ag+ + [NO3]-)(aq) ---------- Ag2S(S) + 2 (Na+ + [NO3]-)(aq) + H2O
The net ionic equation for sodium sulfate (Na2SO4) and barium chloride (BaCl2) when a precipitate of barium sulfate (BaSO4) is formed is: Ba^2+ + SO4^2- → BaSO4 The spectator ions (Na^+ and Cl^-) are not included in the net ionic equation because they do not participate in forming the precipitate.
The net ionic equation for the given reaction would be: H+ + OH- -> H2O
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
OH- + H+ H2O
NaCN + H2O ---> CN-+ H3O++ Na+ In that equation Na+ is just a spectator ion,, further reaction with water results in: CN- + H2O ---> HCN + OH- thus causing the resulting equation to be basic
To write the net ionic equation for NaOH + H2C4H4O6, first write the balanced molecular equation: NaOH + H2C4H4O6 -> NaC4H4O6 + H2O. Then, split the compounds into ions and remove spectator ions: Na+ + OH- + H2C4H4O6 -> Na+ + C4H4O6^2- + H2O. The net ionic equation is OH- + H2C4H4O6 -> C4H4O6^2- + H2O.
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
When sodium hydroxide reacts with hydrochloric acid, they undergo a neutralization reaction to form sodium chloride (NaCl) and water (H2O). The ionic equation for this reaction is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) + energy
The complete ionic equation is: Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq) + H2O(l) -> Na+(aq) + Cl-(aq) + H2O(l) In this reaction, the NaOH dissociates into Na+ and OH- ions, and HCl dissociates into H+ and Cl- ions. The H+ ion reacts with the OH- ion to form water, which results in the net ionic equation shown above.
HClO4(aq) + NaOH(aq) → H2O(l) + NaClO4(aq) Ionic Equation: H+ + ClO4- + Na+ + OH- → H2O + Na+ + ClO4-
The net ionic equation for Na^+ + Cl^- is Na^+ + Cl^- → NaCl, which represents the formation of sodium chloride when Na^+ and Cl^- ions combine. This equation shows the reactants and products without including spectator ions that do not participate in the reaction.
The net ionic equation for perchloric acid (HClO4) and sodium hydroxide (NaOH) is: H+(aq) + OH-(aq) → H2O(l). This represents the reaction between the hydronium ion and hydroxide ion to form water.
The net ionic equation for NaOH (sodium hydroxide) in water is: Na⁺ + OH⁻ → NaOH. This represents the dissociation of sodium ion and hydroxide ion to form sodium hydroxide in solution.