The chemical formula of barium fluoride is BaF2.
Chat with our AI personalities
The chemical formula for barium fluoride is BaF2. It consists of one barium atom (Ba) and two fluoride atoms (F).
The chemical formula for fluorine is F2, indicating it exists as a diatomic molecule. The chemical formula for barium is Ba.
To determine the number of fluoride ions in 175 g of barium fluoride, first calculate the number of moles of barium fluoride using its molar mass. Then, use the ratio of fluoride ions to barium fluoride in the formula BaF\u2082 to find the number of fluoride ions. Finally, multiply this by Avogadro's number (6.022 x 10^23) to get the total number of fluoride ions.
The element E is likely barium (Ba), as its electron configuration is Kr 5s2. The fluoride compound of barium would be BaF2, with barium losing its two valence electrons to form a 2+ cation and fluoride gaining one electron to form a 1- anion.
The formula for hydrogen fluoride is HF.
The formula for gold is Au and the formula for fluoride is F-. When they combine, they form the ionic compound gold(III) fluoride, which has the formula AuF3.