[Xe] 6s2 5f1 <= This is for Cs = Cesium, element number 55, alkali metal
In (K,L,M,N,O) notation: 2, 8, 18, 18, 8, 1
Correct answer:
Ce means Cerium, element number 58, symbol Ce (second of the Lanthanides):
Electron configuration: (K,L,M,N,O,P) 2, 8, 18, 19, 9, 2
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Ground state electron configuration for cerium:
[Xe].1s22s22p63s23p64s23d104p65s24d105p66s25d14f1
The 4f1 configuration represents the ground state, mostly due to the nonbonding nature of the corresponding atomic orbital whose electron density, perpendicular to the molecular plane, minimizes the electrostatic repulsion between the unpaired 4f metal electron and e.g. the halogen pairs in CeHal3 molecule.
Atom number 58, Ce has 58 electrons
Per shell: (K, L, M, N, O, P) = 2, 8, 18, 19, 9, 2
Configuration [period 6, group 3, Lanthanides]:
[1s2 ] [2s2 2p6 ] [3s2 3p6 ] [3d10 4s2 4p6 ] [5s2 4d10 5p6 ] [4f2 6s2 ]
The valence electronic configuration is the arrangement of electrons int the outer most shell of the atom . The electronic configuration of cerium is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 4f1 5d1 6s2.
Cerium's atomic number is 58. Thus, it has 58 protons and 58 electrons. Filling in the first 58 electron orbitals gives the electron configuration of 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f1 5d1.
The element cesium (or caesium, atomic number 55) has the electron configuration
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 6s1
or abbreviated as [Xe] 6s1
The electron configuration of cesium is [Xe] 6s1. This means that it has a full outer shell of electrons in the 6s orbital, making it highly reactive.
Electrons per shell: 2, 8, 18, 19, 9, 2
configuration (shorthand) [Xe] 4f1 5d1 6s2
A cesium atom has 1 valence electron. It is an alkali metal, and all alkali metals have 1 valence electron. The electron configuration for cesium is (Rn)7s1. The single electron in the 7s sublevel is its valence electron.
Cesium has one unpaired electron.
Cesium forms Cs+ ions, as it typically loses one electron to achieve a stable electron configuration. It is highly unlikely for cesium to form Cs2+ ions as this would require the loss of two electrons, which is energetically unfavorable.
Cesium and sulfur are unlikely to form a bond since cesium is a highly reactive metal that tends to lose an electron to obtain a stable electron configuration, while sulfur is a non-metal that tends to gain electrons. This difference in reactivity makes it unlikely for them to form a stable bond together.
Xe, Ba2+