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It is not complete...ammonium sulfate is (NH4)2SO4

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Myra Bradtke

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3y ago
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7mo ago

(NH4)2SO4 is ammonium sulfate, a chemical compound commonly used as a fertilizer due to its high solubility in water and rich source of nitrogen and sulfur for plants. It can also be used in various industrial applications such as in the manufacturing of pharmaceuticals and food additives.

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15y ago
AnswerAmmonium sulphate.
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Q: What is (NH4)2SO4?
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Related questions

What name of the element NH42SO4?

The name of the compound NH4HSO4 is ammonium bisulfate.


How many moles of (NH4)2SO4 do you have?

0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.


What is the net charge of NH42SO4?

there is no charge. NH4 has a plus one charge and sulfate (SO4) has a minus two charge. since there is two NH4 the charges balance out


Is NH42SO4 alkaline or acidic or neutral?

NH4HSO4 is acidic. When dissolved in water, it forms ammonium ion (NH4+) and hydrogen sulfate ion (HSO4-), which can donate a hydrogen ion (H+) to the solution, making it acidic.


Is NH42SO4 ionic?

These species are both polyatomic ions. NH4 + (ammonium ) and SO4 2- ( sulfate ) combine with opposite charges to form (NH4)2SO4 which is ammonium sulfate a polyatomic ionic bonding.


What is the correct name for a compound with the formula NH42SO4?

The correct name for the compound NH4₂SO4 is Ammonium sulfate.


What is the formula mass for ammonium sulfate NH42SO4 which is used in the biochemical treatment of wastewater?

The formula mass of ammonium sulfate (NH4)2SO4 is calculated by adding the atomic masses of each element present in the compound. For (NH4)2SO4, the atomic masses are: N=14, H=1, S=32, O=16. Adding 2(N) + 8(H) + S + 4(O) gives a total formula mass of 132 g/mol.


Inorganic Chemistry How many moles in 50 grams of NH4 2SO4?

To find the number of moles in 50 grams of (NH4)2SO4, first calculate the molar mass of (NH4)2SO4. (NH4)2SO4 has a molar mass of 132.14 g/mol. Next, use the formula: moles = mass / molar mass. So, moles = 50 g / 132.14 g/mol, which is approximately 0.378 moles of (NH4)2SO4.


What solutions have the lowest freezing point 0.012m nh42so4 or 0.012m ceno34?

The solution with the lower freezing point would be the one with the higher van't Hoff factor. In this case, the van't Hoff factor for NH4 2SO4 is 3 (2 for NH4+ and 1 for SO4^2-), while the van't Hoff factor for Ce(NO3)4 is 5 (1 for Ce^4+ and 4 for NO3^-). Therefore, 0.012 M Ce(NO3)4 would have the lower freezing point.