The correct name for the compound NH4₂SO4 is Ammonium sulfate.
The formula mass of ammonium sulfate (NH4)2SO4 is calculated by adding the atomic masses of each element present in the compound. For (NH4)2SO4, the atomic masses are: N=14, H=1, S=32, O=16. Adding 2(N) + 8(H) + S + 4(O) gives a total formula mass of 132 g/mol.
The name of the compound NH4HSO4 is ammonium bisulfate.
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
there is no charge. NH4 has a plus one charge and sulfate (SO4) has a minus two charge. since there is two NH4 the charges balance out
NH4HSO4 is acidic. When dissolved in water, it forms ammonium ion (NH4+) and hydrogen sulfate ion (HSO4-), which can donate a hydrogen ion (H+) to the solution, making it acidic.
These species are both polyatomic ions. NH4 + (ammonium ) and SO4 2- ( sulfate ) combine with opposite charges to form (NH4)2SO4 which is ammonium sulfate a polyatomic ionic bonding.
The correct name for the compound NH4₂SO4 is Ammonium sulfate.
The formula mass of ammonium sulfate (NH4)2SO4 is calculated by adding the atomic masses of each element present in the compound. For (NH4)2SO4, the atomic masses are: N=14, H=1, S=32, O=16. Adding 2(N) + 8(H) + S + 4(O) gives a total formula mass of 132 g/mol.
To find the number of moles in 50 grams of (NH4)2SO4, first calculate the molar mass of (NH4)2SO4. (NH4)2SO4 has a molar mass of 132.14 g/mol. Next, use the formula: moles = mass / molar mass. So, moles = 50 g / 132.14 g/mol, which is approximately 0.378 moles of (NH4)2SO4.
The solution with the lower freezing point would be the one with the higher van't Hoff factor. In this case, the van't Hoff factor for NH4 2SO4 is 3 (2 for NH4+ and 1 for SO4^2-), while the van't Hoff factor for Ce(NO3)4 is 5 (1 for Ce^4+ and 4 for NO3^-). Therefore, 0.012 M Ce(NO3)4 would have the lower freezing point.