The copper will eventually be replaced by the silver in the solution.
Cu + 2Ag2 --> 2Ag + Cu2+
The copper atoms will be oxidized (lose electrons) to form copper ions, while the silver ions will be reduced (gain electrons).
Oxidized: Cu -->Cu2+ + 2e-
Reduced:2(Ag+ + e- ---> Ag)
It's said the solution turns blue in the experiiment, but I didn't see that when I tried this experiment.
Also, this would not be a good way to get rich;(replacing copper with silver in the silver nitrate and then selling it, that is) the silver nitrate is more expensive than silver itself.
When copper wire is dipped in ferrous sulfate solution, a displacement reaction occurs where copper displaces iron from ferrous sulfate, forming copper sulfate and iron. As a result, the copper wire will become coated with a reddish-brown deposit of iron.
When Iron metal is dipped into a solution of copper sulfate a REDOX reaction occurs in which the Copper is reduced (gains electrons) and the iron is oxidised (loses electrons). When this happens, the iron metal becomes iron ions and the copper ions in the solution become copper metal. Cu2+(aq) + 2e- --> Cu(s) Fe(s) -->Fe2+(aq) + 2e- This occurs because the iron is a more active metal than copper, and as a general rule of thumb, a more reactive metal will displace a less reactive metal from solution. This principle underlies the action of the sacrificial electrode.
When an iron nail is dipped in the solution of copper sulphate solution , after a while the solution changes into the colour of green becoming iron sulphate and a brown substance is found on the iron nail which is copper so we get to know that the displacement reaction is produced
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When an iron nail is dipped in copper sulfate solution, a displacement reaction occurs. The iron nail will displace the copper from the copper sulfate solution to form iron sulfate solution and copper metal deposits on the nail. This reaction is represented by the equation: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s).
If a copper coin is dipped in silver nitrate solution for hours or days, the solution will likely turn blue due to the formation of copper(II) nitrate. This reaction occurs as copper from the coin reacts with the silver nitrate in the solution.
When gold is dipped into a solution of copper sulfate, a redox reaction occurs where copper ions in the solution gain electrons and are reduced to solid copper metal. The gold does not react and remains unchanged in the solution.
When zinc is dipped in a copper sulfate solution, zinc will undergo a single displacement reaction where it will replace copper in the solution to form zinc sulfate and copper. This is because zinc is higher on the activity series than copper, so it is able to displace copper in the solution.
When copper wire is dipped in ferrous sulfate solution, a displacement reaction occurs where copper displaces iron from ferrous sulfate, forming copper sulfate and iron. As a result, the copper wire will become coated with a reddish-brown deposit of iron.
When a silver plate is dipped in a copper sulphate solution, a redox reaction occurs where silver ions gain electrons from copper metal. This causes the silver ions to be reduced and deposit silver onto the plate, while the copper metal loses electrons and forms copper ions in the solution. Over time, the silver plate will become coated with a layer of silver.
When a iron nail is dipped into copper sulphate solution after sometime the colour is changed into pale green.
When Iron metal is dipped into a solution of copper sulfate a REDOX reaction occurs in which the Copper is reduced (gains electrons) and the iron is oxidised (loses electrons). When this happens, the iron metal becomes iron ions and the copper ions in the solution become copper metal. Cu2+(aq) + 2e- --> Cu(s) Fe(s) -->Fe2+(aq) + 2e- This occurs because the iron is a more active metal than copper, and as a general rule of thumb, a more reactive metal will displace a less reactive metal from solution. This principle underlies the action of the sacrificial electrode.
When an iron nail is dipped in the solution of copper sulphate solution , after a while the solution changes into the colour of green becoming iron sulphate and a brown substance is found on the iron nail which is copper so we get to know that the displacement reaction is produced
There would be no reaction because copper is a less reactive metal than iron. Refer to the related link for an activity series of metals.
When an iron nail is dipped in copper sulphate solution, a displacement reaction occurs where the iron displaces copper from the copper sulphate solution. This results in the formation of copper metal on the surface of the iron nail, causing the nail to become coated with a layer of copper.
When an iron nail is placed in a copper sulphate solution, iron displaces copper from copper sulphate solution forming iron sulphate, which is green in colour.Therefore, the blue colour of copper sulphate solution fades and green colour appears.
When zinc is dipped in silver nitrate, a displacement reaction occurs where zinc atoms replace silver ions in solution. This results in the formation of zinc nitrate and silver metal. The silver metal will coat the surface of the zinc, creating a silver-colored coating.