Sodium sulfate powder is white.
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To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
The polyatomic ion Na2SO4 is called sodium sulfate.
The balanced equation for CaSO4 + 2NaCl is CaCl2 + Na2SO4.
To find the grams of sodium in 0.820 moles of Na2SO4, first calculate the molar mass of Na2SO4: 2(Na) + 1(S) + 4(O) = 2(23) + 32 + 4(16) = 142 g/mol. Since each mole of Na2SO4 contains 2 moles of Na atoms, the molar mass of Na in Na2SO4 is 46 g/mol. Therefore, in 0.820 moles of Na2SO4, there are 0.820 moles * 2 moles Na * 46 g/mol = 75.32 grams of sodium.
There are approximately (1.93 \times 10^{24}) atoms in 3.2 moles of Na2SO4. This value is calculated using Avogadro's number (6.022 x 10^23 atoms/mol) and the formula weight of Na2SO4.