To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
The polyatomic ion Na2SO4 is called sodium sulfate.
The balanced equation for CaSO4 + 2NaCl is CaCl2 + Na2SO4.
To find the grams of sodium in 0.820 moles of Na2SO4, first calculate the molar mass of Na2SO4: 2(Na) + 1(S) + 4(O) = 2(23) + 32 + 4(16) = 142 g/mol. Since each mole of Na2SO4 contains 2 moles of Na atoms, the molar mass of Na in Na2SO4 is 46 g/mol. Therefore, in 0.820 moles of Na2SO4, there are 0.820 moles * 2 moles Na * 46 g/mol = 75.32 grams of sodium.
There are approximately (1.93 \times 10^{24}) atoms in 3.2 moles of Na2SO4. This value is calculated using Avogadro's number (6.022 x 10^23 atoms/mol) and the formula weight of Na2SO4.
To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.
First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
The chemical name for Na2SO4 is sodium sulfate.
When Na2SO4 dissolves in water, it dissociates into two Na+ ions and one SO4 2- ion. The dissociation equation is: Na2SO4 (s) -> 2Na+ (aq) + SO4 2- (aq).
The chemical formula for sodium sulfate is Na2SO4.
The chemical formula for sodium sulfate is Na2SO4.
To find the number of moles of Na2SO4 in 25.0 g of the compound, you need to convert the mass to moles. First, determine the molar mass of Na2SO4, then divide the given mass by the molar mass to obtain the number of moles.
The balanced chemical equation for the reaction between sulfuric acid (H2SO4) and sodium hydrogen carbonate (NaHCO3) is: 2H2SO4 + 2NaHCO3 → Na2SO4 + 2H2O + 2CO2
inorganic
Na2SO4
The polyatomic ion Na2SO4 is called sodium sulfate.