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The molar mass of aluminum sulfate, Al2(SO4)3, can be calculated by adding together the atomic masses of all the elements in the compound. Aluminum has a molar mass of 26.98 g/mol, sulfur has a molar mass of 32.06 g/mol, and oxygen has a molar mass of 16.00 g/mol. By calculating the total molar mass, the molar mass of aluminum sulfate is found to be approximately 342.14 g/mol.
Aluminum sulfate is an ionic compound that does not have true moles. Its formula unit mass is 342.14, for the anhydrous form.
The relative masses of sodium, aluminum and sulfate are 23, 27 and 96 respectively. The RMM of sodium sulfate is 144 grams per mole. That of aluminum sulfate is 273 grams per mole.
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What is the mass of 0.25 moles of aluminum sulphate?
To find the mass of 0.25 moles of aluminum sulfate, you need to know the molar mass of aluminum sulfate. The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be around 85.54 grams.
The formula for aluminum sulfate is Al2 SO4 3 figure the molar mass of aluminum sulfate to the nearest gram?
To calculate the molar mass of aluminum sulfate (Al2(SO4)3), you need to sum the atomic masses of all the elements in the formula. The atomic mass of aluminum (Al) is 26.98 g/mol, sulfur (S) is 32.07 g/mol, and oxygen (O) is 16.00 g/mol. The molar mass of Al2(SO4)3 = 2(26.98) + 3(32.07 + 4(16.00)) = 2(26.98) + 3(32.07 + 64.00) = 54.96 + 3(96.07) = 54.96 + 288.21 = 343.17 g/mol. Therefore, the molar mass of aluminum sulfate to the nearest gram is 343 g/mol.
What is the molar mass of aluminum chloride?
The molar mass of aluminum chloride (AlCl3) is 133.34 g/mol. This is calculated by adding the atomic masses of one aluminum atom and three chlorine atoms.
The molar mass of aluminum chloride is?
The molar mass of aluminum chloride (AlCl3) is approximately 133.34 g/mol.
How many moles is 44.78g of cupric sulfate?
To find the number of moles, you need to divide the given mass (44.78g) by the molar mass of cupric sulfate. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. Therefore, 44.78g of cupric sulfate is approximately 0.28 moles.
What is the molar mass aluminum sulfate?
342.15
What is the mass of 0.25 moles of aluminum sulphate?
To find the mass of 0.25 moles of aluminum sulfate, you need to know the molar mass of aluminum sulfate. The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be around 85.54 grams.
What is the molar mass of aluminum sulfate to the nearest gram?
The molar mass of aluminum sulfate (Al2(SO4)3) is approximately 342 grams per mole.
6.7 grams of aluminum sulfate to moles?
To convert grams of aluminum sulfate to moles, you first need to determine the molar mass of aluminum sulfate (Al2(SO4)3), which is approximately 342.15 g/mol. Then, divide the given mass by the molar mass to obtain the number of moles. In this case, 6.7 grams of aluminum sulfate is approximately 0.02 moles.
How many moles of Sulfur are in 2.55g of aluminum sulfate?
To find the number of moles of sulfur in 2.55g of aluminum sulfate, you need to first calculate the molar mass of aluminum sulfate (Al2(SO4)3), which is 342.15 g/mol. Sulfur accounts for 3 moles in one mole of aluminum sulfate, so you can calculate the number of moles by dividing the given mass (2.55g) by the molar mass of aluminum sulfate.
What is the mass of 0.25 mole of aluminum sulfate?
The molar mass of aluminum sulfate is 342.15 g/mol. Therefore, the mass of 0.25 moles of aluminum sulfate would be 85.54 grams (0.25 moles x 342.15 g/mol).
How many milligrams of aluminum are present in 5.60 grams of aluminum sulfate?
In aluminum sulfate, the molar mass of aluminum is 27 g/mol. Calculate the amount of aluminum in 5.60 g of aluminum sulfate using the molar ratio between aluminum and aluminum sulfate (1:1). Therefore, there are 5.60 grams of aluminum in 5.60 grams of aluminum sulfate.
How many grams of aluminum is required to produce 25.0 grams of aluminum sulfate?
To find the amount of aluminum needed to produce aluminum sulfate, you need to consider the molar mass of aluminum sulfate and the ratio of aluminum in the compound. First, calculate the molar mass of aluminum sulfate (Al2(SO4)3). Then, find the ratio of aluminum in the compound (2 moles of Al in 1 mole of Al2(SO4)3). Finally, use this information to calculate the grams of aluminum needed to produce 25.0 grams of aluminum sulfate.
The formula for aluminum sulfate is Al2 SO4 3 figure the molar mass of aluminum sulfate to the nearest gram?
To calculate the molar mass of aluminum sulfate (Al2(SO4)3), you need to sum the atomic masses of all the elements in the formula. The atomic mass of aluminum (Al) is 26.98 g/mol, sulfur (S) is 32.07 g/mol, and oxygen (O) is 16.00 g/mol. The molar mass of Al2(SO4)3 = 2(26.98) + 3(32.07 + 4(16.00)) = 2(26.98) + 3(32.07 + 64.00) = 54.96 + 3(96.07) = 54.96 + 288.21 = 343.17 g/mol. Therefore, the molar mass of aluminum sulfate to the nearest gram is 343 g/mol.
What molar mass of iron ii sulfate?
The molar mass of iron(II) sulfate (FeSO4) is 151.91 g/mol.
The molar mass of aluminum chloride is grams?
The molar mass of aluminum chloride (AlCl3) is 133.34 grams/mol.
What is the molar mass of chromic sulfate?
The molar mass of chromic sulfate (Cr2(SO4)3) is approximately 392.15 g/mol.
