When Na2S2O5 (sodium metabisulfite) reacts with H2O2 (hydrogen peroxide), it undergoes a redox reaction where the sulfur in Na2S2O5 is oxidized by H2O2. The overall reaction produces sulfuric acid (H2SO4) as one of the products. The pH effect would depend on the specific concentrations of Na2S2O5, H2O2, and the buffering capacity of the solution, but generally, the reaction would likely result in the pH decreasing due to the formation of sulfuric acid.
The balanced equation for the reaction N2H4 + H2O2 forms N2 + H2O is: 3N2H4 + 4H2O2 -> 3N2 + 8H2O. The coefficients are 3, 4, 3, and 8, respectively.
The chemical reaction shown is a combination reaction, where two or more substances combine to form a single product. In this case, hydrogen gas (H2) and oxygen gas (O2) combine to form hydrogen peroxide (H2O2).
Hydrogen peroxide (H2O2) is the substrate in the given equation. It is broken down into water (H2O) and oxygen (O2) by the enzyme catalase.
H2O2 The cation hydrogen has a charge of +1, and the anion peroxide has a charge of -2, so to balance peroxide's charge we would need two hydrogen atoms, as the net (total) charge of a compound must always be zero. I am, however, unsure if peroxide is indeed an anion, but the rest of the information is correct. Look it up if in doubt.
Balanced:2 C2H2 + 5 O2 ----> 4 CO2 + 2H2O
The balanced equation for the reaction is: N2H4 + H2O2 -> N2 + H2O The coefficients for the balanced equation are: 1 N2H4 + 1 H2O2 -> 1 N2 + 2 H2O
The balanced equation for the reaction N2H4 + H2O2 forms N2 + H2O is: 3N2H4 + 4H2O2 -> 3N2 + 8H2O. The coefficients are 3, 4, 3, and 8, respectively.
The products of the reaction between KIO3 and Na2S2O5 in the iodine clock reaction are I2, NaIO3, Na2SO4, and H2O. The reaction involves the oxidation of S2O32- by I3- to produce I2, resulting in the color change characteristic of the iodine clock reaction.
Catalase breaks down hydrogen peroxide into water and oxygen. Therefore, its substrate in this reaction is hydrogen peroxide (H2O2).
The reaction is:2 H2O2-----------------2 H2O + O2
The product of the reaction between hydrogen peroxide (H2O2) and manganese dioxide (MnO2) is oxygen gas (O2) and water (H2O).
The chemical reaction shown is a combination reaction, where two or more substances combine to form a single product. In this case, hydrogen gas (H2) and oxygen gas (O2) combine to form hydrogen peroxide (H2O2).
It is very clear: the compounds resulted from this reaction are water and oxygen.
The reaction between hydrogen peroxide (H2O2) and manganese dioxide (MnO2) is a decomposition reaction that produces oxygen gas (O2) in the form of bubbles. The oxygen gas then reacts with the carbon in the air to produce carbon dioxide (CO2) when a flame is introduced.
If you start with 4 H2O2 molecules, you would end up with 2 O2 molecules. This is because for every 2 molecules of H2O2 that decompose, 1 molecule of O2 is produced.
2H2O2 in the prescence of catalase results in 2 H2O + O2
If you had the equation of H2O2(aq) ==> H2O(l) + O2(g), it wouldn't be balanced, so is incorrect. If it were 2H2O2 ==> 2H2O + O2, then it would be balanced, and H2O2 would be an example of a disproportionation reaction, where H2O2 is both the oxidizing and reducing agent, i.e., the O is both oxidized and reduced to form H2O and O2. Not sure if this is what you are looking for as the question is rather vague.