The solubility of sodium nitrate in benzene is likely extremely low. I know that its solubility in dry acetonitrile (<40 ug/mL H2O) is less than 1 mg/mL. So I would guess it would be even worse in a non-polar solvent like benzene.
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No, sodium iodide is not soluble in benzene. Sodium iodide is a polar compound due to the ionic bonding between sodium and iodine, making it insoluble in nonpolar solvents like benzene.
Benzene is a non polar solvent. Sodium iodide is an ionic salt. So, this salt is unsoluble in benzene.
Sodium iodide is highly soluble in water, with a solubility of approximately 184 grams per 100 mL of water at room temperature. This high solubility is due to the strong ionic interactions between the sodium cation and the iodide anion with water molecules.
The reaction between silver nitrate and sodium iodide will result in the formation of silver iodide precipitate and sodium nitrate solution. This is a double displacement reaction where the silver ions from silver nitrate will combine with iodide ions from sodium iodide to form the insoluble silver iodide.
The precipitate formed when sodium hydroxide reacts with potassium iodide is brown.
The chemical name of Nal is Naltrexone.
No, lithium iodide is not soluble in acetone. Lithium iodide is generally soluble in water, but it has limited solubility in organic solvents like acetone.