How many nitrogen atoms are in 10.2 g of copper(II) nitrate?

Answer 1

A mole of any element contains 6.022*1023 (Avogadro's Number) atoms of that element.

So a mole of copper would contain 6.022*1023 atoms of copper.

Answer 2

There are 2 nitrogen atoms in 1 molecule of copper(II) nitrate (Cu(NO3)2). To find the number of nitrogen atoms in 10.2 g of Cu(NO3)2, you first need to calculate the number of moles of Cu(NO3)2 in 10.2 g, then use the mole ratio to find the number of nitrogen atoms. The molar mass of Cu(NO3)2 is 187.56 g/mol.

Answer 3

multiply 6 times 10 to the power of 23 [6 x 1023] to the moles of your copper nitrate

Answer 4

There are nine atoms in Copper(II) Nitrate, six oxygen, two nirtogen, and one copper. The formula is Cu(NO3)2.

Answer 5

187.56 g/mol

Answer 6

1 mole of anything is 6.022 X 10^23

Answer 7

1 mol Cu Atoms (6.02x10^23 atoms)

Answer 8

it contains 9 atoms

Answer 9

6.55 x 10^22 atoms

Answer 10

2