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The formula given shows that each formula unit of KCl contains one atom of potassium. Therefore, the number of moles of potassium will be the same as the number of moles of KCl, and its gram formula mass is 74.55. therefore, the number of moles is 125/74.55 or 1.68, to the justified number of significant digits.
To find the moles of potassium in 125g of KCl, first calculate the molar mass of KCl (39.1 g/mol for K + 35.5 g/mol for Cl = 74.6 g/mol). Next, divide the given mass by the molar mass to find the moles: 125g / 74.6 g/mol ≈ 1.68 moles of KCl. Since there is 1 mole of K for every mole of KCl, there are approximately 1.68 moles of potassium in 125g of KCl.
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How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?
To find the volume of 0.25M KCl needed to provide 0.012 moles of KCl, you can use the formula: moles = Molarity x Volume (in liters). Rearranging this formula to solve for Volume gives Volume = moles / Molarity. Plugging in the values, Volume = 0.012 moles / 0.25 mol/L = 0.048 L = 48 ml.
How many moles are in 74 g of KCl?
To find the number of moles in 74 g of KCl, you first need to calculate the molar mass of KCl. The molar mass of KCl is approximately 74.55 g/mol. Then, divide the given mass by the molar mass to get the number of moles: 74 g / 74.55 g/mol ≈ 0.993 moles.
How many grams of KCl to make 50 mL of 2.45 M KCl?
To calculate the grams of KCl needed, first calculate the moles of KCl required using the molarity formula. Then, convert moles to grams using the molar mass of KCl, which is approximately 74.55 g/mol.
How many moles of KCl are dissolved in 1.20 L of a 0.400 M KCl solution?
To calculate the amount of moles of potassium chloride in a 0.400 M KCl (aq) solution, you may use equation (1) belown = c * v (1)where n equals the amount of moles, c is the concentration of the solution and v is the volume.We have the volume and the concentration, which renders us able to solve the equation:n = 0.400 * 1.2 Ln = 0.48 moles.
How many mols in 74g of KCl?
1 mole.
How many moles of KCl are contained in 0.635L of 2.2M KCl?
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
How many moles of KCl are contained in 1.7L of a 0.83M KCl solution?
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
How many moles of KCl are contained in 121mL of a 1.68M KCl solution?
Molarity is moles of solute per L of solution.moles KCl = ( 1.68 M ) ( 0.121 L ) = ( 1.68 mol/L ) ( 0.121 L )moles KCl = 0.203 moles KCl
How many moles of KCl in 0.90M KCl?
The answer is of course 0,9 M.
How many moles of KCl will be formed from 0.440 moles of KClO3?
1 mole of KClO3 produces 1 mole of KCl upon decomposition. Therefore, 0.440 moles of KClO3 will produce 0.440 moles of KCl.
How many grams are in 3.75 moles of kcl?
To find the number of grams in 3.75 moles of KCl, you would first calculate the molar mass of KCl, which is approximately 74.55 g/mol. Then, you would multiply this molar mass by the number of moles (3.75 moles) to get the answer, which is 279.56 grams of KCl.
How many moles are in 48g of KCl?
KCl has a molar mass of 39+35.5=74.5g/mol, and 48/74.5=0.64mol.
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
How many moles of KCl are present in 50.0 mL of a 0.552 M solution?
To find the moles of KCl in the solution, we first calculate the amount of KCl in 50.0 mL using the concentration. Volume (in liters) = 50.0 mL / 1000 = 0.050 L. Moles of KCl = Concentration x Volume = 0.552 mol/L x 0.050 L = 0.0276 moles of KCl.
How many moles of KCl are contained in a 0.630L of a 2.3M KCl solution?
To find the moles of KCl in the solution, we use the formula: Moles = Molarity x Volume (in liters). Plugging in the values, Moles = 2.3 mol/L x 0.630 L = 1.449 mol of KCl in 0.630 L of a 2.3M KCl solution.
How many moles are in 12.57 grams of KC1?
To find the number of moles in 12.57 grams of KCl, you need to first calculate the molar mass of KCl which is approximately 74.55 g/mol. Then, divide the given mass (12.57g) by the molar mass to get the number of moles, which is approximately 0.1685 moles.
How many ml of 0.25M KCl are needed to provide 0.012 moles of KCl?
To find the volume of 0.25M KCl needed to provide 0.012 moles of KCl, you can use the formula: moles = Molarity x Volume (in liters). Rearranging this formula to solve for Volume gives Volume = moles / Molarity. Plugging in the values, Volume = 0.012 moles / 0.25 mol/L = 0.048 L = 48 ml.
