At standard temperature and pressure (STP), one mole of a gas is 22.4L.
So, in order to determine how many moles of O2 are in 30L, you do the following:
multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
There are 2 moles of oxygen gas and approximately 6.023 x 10^23 molecules in 64 g of oxygen gas.
The answer is 0,173 moles.
6,5 moles oxygen equals 208 g.
The equivalent in moles is 6,03.
The answer is 2 moles.
The mass of 0,2 moles of oxygen gas is 6,4 g.
For every mole of potassium chlorate (KClO3) that decomposes, three moles of oxygen gas (O2) are produced. Therefore, to produce 6 moles of oxygen gas, 2 moles of potassium chlorate are needed.
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
30 moles
To find the number of moles in 16 g of oxygen gas, you need to divide the given mass by the molar mass of oxygen. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 16 g / 32 g/mol = 0.5 moles of oxygen gas.
Four moles of potassium chlorate are needed.
We need 3 moles of potassium perchlorate.
The molar mass of oxygen gas (O2) is 32.00 g/mol. Therefore, the mass of 4.00 moles of oxygen gas is 128.00 grams.