At standard temperature and pressure (STP), one mole of a gas is 22.4L.
So, in order to determine how many moles of O2 are in 30L, you do the following:
multiply 30L O2 x 1mol O2/22.4L O2, which equals 1.34mol O2.
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
The balanced chemical equation for the reaction between ammonia (NH3) and oxygen gas (O2) is 4 NH3 + 5 O2 → 4 NO + 6 H2O. This means that 5 moles of O2 are needed to react with 4 moles of NH3. With 10.0 moles of NH3, you would need 12.5 moles of O2 (10.0 moles NH3 x 5 moles O2 / 4 moles NH3).
I was wondering about this... but I think if you combined..The four oxygen gas O2, and the two of Hydrogen gas H2.. and predict was will happened I guess this is what it will or might be calculate, but Im not sure.KKKO2O2+H2H1O4+H2O2H
2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3
There are 2 moles of oxygen gas and approximately 6.023 x 10^23 molecules in 64 g of oxygen gas.
The answer is 0,173 moles.
6,5 moles oxygen equals 208 g.
The equivalent in moles is 6,03.
The answer is 2 moles.
For every mole of potassium chlorate (KClO3) that decomposes, three moles of oxygen gas (O2) are produced. Therefore, to produce 6 moles of oxygen gas, 2 moles of potassium chlorate are needed.
The mass of 0,2 moles of oxygen gas is 6,4 g.
To find the number of moles of oxygen in 0.16 g of oxygen gas, you first need to determine the molar mass of oxygen (O2), which is about 32 g/mol. Then, you can use the formula moles = mass / molar mass to calculate the number of moles. In this case, 0.16 g / 32 g/mol = 0.005 moles of oxygen gas.
30 moles
To find the number of moles in 16 g of oxygen gas, you need to divide the given mass by the molar mass of oxygen. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 16 g / 32 g/mol = 0.5 moles of oxygen gas.
We need 3 moles of potassium perchlorate.
Four moles of potassium chlorate are needed.
The molar mass of oxygen gas (O2) is 32.00 g/mol. Therefore, the mass of 4.00 moles of oxygen gas is 128.00 grams.