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To find the number of moles of Na in 42g of Na, you would first calculate the molar mass of Na (sodium is 22.99 g/mol), and then divide the given mass by the molar mass.
moles of Na = 42g / 22.99 g/mol ≈ 1.83 moles
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How many moles of Na are in 42 grams of Na?
To find the number of moles of Na in 42 grams, we can use the molar mass of Na, which is approximately 23 grams/mol. First, calculate the number of moles by dividing the given mass by the molar mass: 42 grams / 23 grams/mol = 1.83 moles of Na.
How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen This is the formula for the reaction?
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
How many moles of Na are in 15 g of NaCl?
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
How many atoms are in 0.188 moles Na?
There are approximately 1.13 x 10^22 atoms in 0.188 moles of sodium (Na). This is calculated by multiplying Avogadro's number (6.022 x 10^23 atoms/mol) by the number of moles.
How many moles of ions are in 2.5 mol of NaCl?
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
How many moles in 14.625 grams of Na CI?
The answer is 0,25 moles.
How many moles of Na contain 7.88x1021 atoms of Na (to find moles, divide atoms by Avogadro's number)?
0.013089701
How many moles of Na are in 42 grams of Na?
To find the number of moles of Na in 42 grams, we can use the molar mass of Na, which is approximately 23 grams/mol. First, calculate the number of moles by dividing the given mass by the molar mass: 42 grams / 23 grams/mol = 1.83 moles of Na.
How many moles are in 4.99 g of Na?
To find the number of moles in 4.99 g of Na, divide the mass by the atomic mass of Na. The atomic mass of Na is 22.99 g/mol. Thus, 4.99 g of Na is equal to 0.217 moles.
How many moles of hydrogen gas will be produced if 25g of Na reacts completely with excess HCl?
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
How many moles of sodium oxide will be produced when 10 moles of sodium react with oxygen This is the formula for the reaction?
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
How many Na atoms are there in 0.125 moles of Na metal?
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
How many moles of Na Cl could be made by combining 20000 mole of Na with 2 moles of Cl?
You can make 2 moles of NaCl by combining 20000 moles of Na with 2 moles of Cl because the balanced chemical equation for this reaction is 2Na + Cl2 -> 2NaCl.
How many moles of Na are in 15 g of NaCl?
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
How many moles of Na are needed to make 4 moles of H2?
2 moles of Na are needed to make 4 moles of H2, based on the balanced chemical equation for the reaction between Na and H2.
If 250ml of solution contains 42g of Magnesium nitrate calculate the concentration of nitrate ions?
To calculate the concentration of nitrate ions, we first need to find the molar mass of Mg(NO3)2, which is approximately 148.33 g/mol. Next, we calculate the number of moles of Mg(NO3)2 in 42g, which is 42g/148.33 g/mol = 0.283 moles. Since there are 2 nitrate ions per Mg(NO3)2, the number of moles of nitrate ions is 0.283 moles x 2 = 0.566 moles. Finally, we divide the moles of nitrate ions by the volume of solution in liters (0.25 L) to get the concentration: 0.566 moles / 0.25 L = 2.26 M.
How many oz in 42g.?
There are approximately 1.48 ounces in 42 grams.
