First start with what you know to find the total moles.
Mn = 54.94g
O = 16g
54.94g * 2 = 109.88g
16 * 3 = 48g
Add these to get the weight of Mn2O3 which = 157.88
Divide 157.88 / 286 to get your total moles present, which = .552 Mols
To find moles Mn, divide 54.94 by the total weight which is 157.88. This gives you your moles Mn, which is .348 mols. Since you have Mn2, multiply that number by 2 to get .695 mols
Now you can divide Mol(Mn) by your total moles (.552) to get your moles Mn
So .695 mol Mn2O3 / .552 mol Mn = 1.1 Mol Mn
since 1.1 * 54.94 = 60 pct of the Molar Mass, this number makes sense since there is more Mn than O, the proportion seems correct.
hope this helped!
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16.1201 grams KMnO4 (1 mole KMnO4/158.04 grams)(1 mole Mn/1 mole KMnO4)(6.022 X 1023/1 mole Mn)(1 mole Mn atoms/6.022 X 1023)
= 0.102000 moles of manganese atoms
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Note that Avogadro's number is actually over itself in a form of one, so you do not need to go all the way in this, a formal set-up.
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
To find the number of moles of phosphorus atoms in 100 grams of P4S10, we first need to determine the molar mass of P4S10 which is 284.26 g/mol. Next, we calculate the number of moles of P4S10 in 100 grams by dividing 100 g by the molar mass to get 0.352 moles of P4S10. Since there are 4 phosphorus atoms in each P4S10 molecule, there are 0.352 moles x 4 = 1.41 moles of phosphorus atoms in 100 grams of P4S10.
To calculate the amount of hydrogen peroxide (H2O2) dissolved, you can use the equation: moles of KMnO4 = moles of H2O2. Firstly, calculate the moles of KMnO4 (given concentration and volume). Then, use the balanced chemical equation to determine the moles of H2O2, as they have a 1:1 stoichiometric ratio. Finally, convert moles of H2O2 to grams using the molar mass to find the amount dissolved in the solution.
To find the number of atoms in 100 grams of gold, you would first calculate the number of moles using the molar mass of gold (197 grams/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, approximately 3.01 x 10^23 atoms of gold are present in 100 grams.
The compound potassium permanganate has chemical formula KMnO4 Molecular mass of KMnO4 = 39.1 + 54.9 + 4(16.0) = 158.0 Mass of KMnO4 = amount of KMnO4 x Molecular mass of KMnO4 = 2.55 x 158.0 = 403g
To calculate the grams of potassium permanganate in 2.20 moles, you would need to know the molar mass of potassium permanganate. The molar mass of potassium permanganate (KMnO4) is about 158.034 g/mol. So, 2.20 moles of KMnO4 is equal to 2.20 moles x 158.034 g/mol = 347.67 grams of potassium permanganate.
To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
To find the moles of KMnO4 in the solution, we first need to calculate the number of moles in 75.0 mL. Moles = Molarity x Volume (in liters) Moles = 0.0950 mol/L x 0.0750 L Moles = 0.007125 mol Therefore, there are 0.007125 moles of KMnO4 present in 75.0 mL of a 0.0950 M solution.
To find the number of oxygen atoms in 17.7g of potassium permanganate (KMnO4), we need to use Avogadro's number and the molar mass of KMnO4. The molar mass of KMnO4 is 158.034 g/mol. Thus, 17.7g of KMnO4 is equal to 0.112 moles. In one mole of KMnO4, there are 4 oxygen atoms. Therefore, in 17.7g of KMnO4, there are 0.112 moles x 4 = 0.448 moles of oxygen atoms. Finally, using Avogadro's number (6.022 x 10^23 atoms/mol), we find that there are approximately 2.7 x 10^23 oxygen atoms in 17.7g of KMnO4.
The molar mass of potassium permanganate (KMnO4) is 158.034 g/mol. The molar ratio between oxygen atoms and KMnO4 is 4:1. Therefore, in 90 g of KMnO4, there are 90/158.034 moles of KMnO4. Multiply this by 4 to find the number of moles of oxygen atoms, then multiply by Avogadro's number to find the number of oxygen atoms.
0,666 moles
To convert grams to atoms, you need to first convert grams of nitrogen to moles using its molar mass (14.01 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, for 2.2 grams of nitrogen: Convert grams to moles: 2.2 g / 14.01 g/mol = 0.157 moles. Convert moles to atoms: 0.157 moles x 6.022 x 10^23 atoms/mol = 9.46 x 10^22 atoms of nitrogen.
To convert atoms to grams using Avogadro's number, you first need to determine the number of moles of atoms by dividing the number of atoms by Avogadro's number (6.022 x 10^23). Then, you can use the molar mass of the element to convert moles to grams using the formula: grams = moles x molar mass.
4,5 moles of copper are equivalent to 285,957 g.
To find the number of moles of atoms in 75.10 grams of chlorine, you need to first determine the molar mass of chlorine. Chlorine has a molar mass of approximately 35.45 g/mol. Next, you can use the formula Moles = Mass / Molar Mass to calculate the moles of chlorine atoms in 75.10 grams. This would result in approximately 2.12 moles of chlorine atoms.