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Yonas has 44.78 g of cupric sulfate How many moles does he have?
To find the number of moles of cupric sulfate, we need to divide the given mass by its molar mass. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. 44.78 g / 159.61 g/mol ≈ 0.281 moles Therefore, Yonas has approximately 0.281 moles of cupric sulfate.
How many moles are in 44.78 g of cupric sulfate?
To find the number of moles in 44.78 g of cupric sulfate (CuSO4), first calculate the molar mass of CuSO4. The molar mass of CuSO4 is 159.61 g/mol. Next, divide the given mass by the molar mass to find the number of moles. Therefore, 44.78 g ÷ 159.61 g/mol = 0.281 moles of CuSO4.
How many moles of plumbous nitrate are required to react with 0.25 moles of cupric sulfate?
The balanced chemical equation for the reaction between plumbous nitrate and cupric sulfate is: Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2 From the equation, we can see that 1 mole of plumbous nitrate (Pb(NO3)2) reacts with 1 mole of cupric sulfate (CuSO4). Therefore, 0.25 moles of cupric sulfate will require 0.25 moles of plumbous nitrate for complete reaction.
How many moles of copper sulfate are needed to make 2.50 Liters of 0.125 moles solution?
To calculate the moles of copper sulfate needed, use the formula: moles = Molarity x Volume. In this case, 0.125 moles/L x 2.50 L = 0.3125 moles of copper sulfate needed for the 2.50 liters of 0.125 moles solution.
How many moles of sodium sulfate are present in 284 g?
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
Yonas has 44.78 g of cupric sulfate How many moles does he have?
To find the number of moles of cupric sulfate, we need to divide the given mass by its molar mass. The molar mass of cupric sulfate (CuSO4) is approximately 159.61 g/mol. 44.78 g / 159.61 g/mol ≈ 0.281 moles Therefore, Yonas has approximately 0.281 moles of cupric sulfate.
Yonas has 44.78 g of cupric sulfate. How many moles does he have?
Cupric sulfate is CuSO4 which has a molar mass of 159.6g/mol. Thus 44.78 g x 1 mol/159.6 g = 0.2806 moles (to 4 significant figures).
How many moles are in 44.78 g of cupric sulfate?
To find the number of moles in 44.78 g of cupric sulfate (CuSO4), first calculate the molar mass of CuSO4. The molar mass of CuSO4 is 159.61 g/mol. Next, divide the given mass by the molar mass to find the number of moles. Therefore, 44.78 g ÷ 159.61 g/mol = 0.281 moles of CuSO4.
How many moles of plumbous nitrate are required to react with 0.25 moles of cupric sulfate?
The balanced chemical equation for the reaction between plumbous nitrate and cupric sulfate is: Pb(NO3)2 + CuSO4 → PbSO4 + Cu(NO3)2 From the equation, we can see that 1 mole of plumbous nitrate (Pb(NO3)2) reacts with 1 mole of cupric sulfate (CuSO4). Therefore, 0.25 moles of cupric sulfate will require 0.25 moles of plumbous nitrate for complete reaction.
How many atoms in Cupric sulfate?
Cupric sulfate, also known as copper(II) sulfate, has the chemical formula CuSO4. It contains one copper atom (Cu), one sulfur atom (S), and four oxygen atoms (O) in one molecule. So, there are a total of six atoms in one molecule of cupric sulfate.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
How many grams of potassium sulfate are there in 25.3 moles?
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
How many moles are 4.12 grams aluminum sulfate?
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
How many moles of copper sulfate are needed to make 2.50 Liters of 0.125 moles solution?
To calculate the moles of copper sulfate needed, use the formula: moles = Molarity x Volume. In this case, 0.125 moles/L x 2.50 L = 0.3125 moles of copper sulfate needed for the 2.50 liters of 0.125 moles solution.
How many moles of anhydrous copper sulfate is produced when 6.4 moles of hydrated copper sulfate is heated?
When hydrated copper sulfate is heated, it loses its water molecules to form anhydrous copper sulfate. Since the molar ratio between the two forms is 1:1, if 6.4 moles of hydrated copper sulfate is heated, 6.4 moles of anhydrous copper sulfate will be produced.
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
